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zvonat [6]
3 years ago
12

After the cart bounces, how far does it roll back up the ramp?

Physics
1 answer:
vodomira [7]3 years ago
5 0
What cart ? What ramp ?
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Assuming motion is on a straight path, what would result in two positive components of a vector?
erastovalidia [21]
Assuming motion is on a straight path, the result of two positive components of a vector would also be a positive value since both are having positive signs and directions. The direction would be the same with the motion as well. Hope this answers the question. Have a nice day.
3 0
3 years ago
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The temperature of the liquid in a container decreases as the liquid evaporates. Use kinetic theory to explain why.
melisa1 [442]

Answer:

Temperature decreases because the number of collision of the molecules decreases as they escape or evaporate. Molecules are in constant motion. Increase in temperature leads to increase in average kinetic energy of the molecules.

6 0
3 years ago
The body contains many small currents caused by the motion of ions in the organs and cells. Measurements of the magnetic field a
RoseWind [281]

Answer:

270 μA

Explanation:

Use the magnetic field due to long, straight wire and solve for current I.

B= \frac{\mu_0I}{2\pi r}

I= \frac{2\pi r B}{\mu_0}

plug in the values

I= \frac{2\pi(5.40\times10^{-2})\times10\times10^{-6}\times10^{-4}}{4\pi\times10^{-7}}

= 2.7×10^{-4)×10^6

=270 μA

The current that flows in the  heart is 270 μA

8 0
3 years ago
A typical helicopter has four blades that rotate at 334 rpm and have a total kinetic energy of 4.55 105 J. What is the magnitude
djyliett [7]

Answer:

the magnitude of the total angular momentum of the blades is <em>743.71 kg·m²</em>

Explanation:

Converting the angular speed into radians per second:

ω = 334 rpm · (2π rad / 1 rev) · (1 min / 60 s)

ω = 34.98 rad/s

The rotational kinetic energy of the blades is given by:

EK = 1/2 I ω²

where

  • I is the moment of inertia
  • ω is the angular speed

Therefore, rearranging the above equation, we get:

1/2 I ω² = EK

I ω² = 2 EK

I = 2(EK) / ω²

I = 2(4.55 × 10⁵ J) / (34.98 rad/s)²

<em>I = 743.71 kg·m²</em>

<em></em>

Therefore, the magnitude of the total angular momentum of the blades is <em>743.71 kg·m²</em>.

5 0
3 years ago
What is the pressure at the bottom of a tank 1-m deep? Take the density of water to be 1000-kg/m^3, and gravitational accelerati
lara31 [8.8K]

To solve this problem we will use the concepts related to hydrostatic pressure. Which determines the pressure of a body at a given depth of a liquid.

Mathematically this can be described as

P= \rho gh

Here

\rho = Density

g = Gravity

h = Height (Depth)

If we replace the values given in the equation we will have to

P = 1000 (9.8)(1)

P = 9800 Pa

Therefore the pressure at the bottom will be 9.8kPa

4 0
3 years ago
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