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abruzzese [7]
4 years ago
8

Explain why radiation is dangerous to humans

Physics
2 answers:
Ronch [10]4 years ago
8 0
Radiation<span>  is dangerouse to humans because when you react with this product it becomes a sickness .</span><span>Ionizing </span>radiation<span> comes in three flavors: alpha particles, beta particles and gamma </span>rays. Alpha particles are the least dangerous<span> in terms of external exposure 
i hope this helped </span>
tia_tia [17]4 years ago
7 0
Radiation damages the cells that make up the human body, it can even cause cancer
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Why is a standard system of measurement important?
Llana [10]
The best answer among the following choices would be A) or the first option Scientists want to share measurements data that they can understand.
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3 years ago
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I need help dudes!
natulia [17]
In the late Devonian Era
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4 years ago
A ray of light strikes a mirror at an angle of 38 to the normal. what is the reflected angle
Sveta_85 [38]
The same 38 degree angle just in the opposite direction
6 0
3 years ago
Now find the electromotive force E2(t) induced across the entirety of solenoid 2 by the change in current in solenoid 1. Remembe
lions [1.4K]

Answer:

E_{2} (t) = -\pi\mu_o} \rho^{2} n_{1}n_{2}L\frac{d }{dt}I_{1}(t)

Explanation:

Consider two solenoids that are wound on a common cylinder as shown in fig. 1. Let the cylinder have radius 'ρ' and length 'L' .

No. of turns of solenoid 1 = n₁

No. of turns of solenoid 1 = n₂

Assume that length of  solenoid is much longer than its radius, so that its field can be determined from Ampère's law throughout its entire length:

\oint \overrightarrow {B}\overrightarrow {(r)}.\overrightarrow {dl}= \mu_{o}I

We will consider the field that arises from solenoid 1, having n₁  turns per unit length. The magnetic field due to solenoid 1 passes through solenoid 2, which has n₂ turns per unit length.

Any change in magnetic flux from the field generated by solenoid 1 induces an EMF in solenoid 2 through Faraday's law of induction:

\oint \overrightarrow {B}\overrightarrow {(r)}.\overrightarrow {dl}= -\frac{d}{dt} \phi _{M}(t)

Consider B₁(t) magnetic feild generated in solenoid 1 due to current I₁(t)

Using:

                                  B_{1}(t) =\mu _{o} nI(t)\\ --- (2)

                           

Flux generated due to magnetic field B₁

                      \phi _{1}(t) = \oint \overrightarrow {B_{1}}.dA\\ ---(3)

area of solenoid = A = \pi \rho^{2}

substituting (2) in (3)

                       \phi _{1}(t) = \mu_{o} \pi \rho^{2} n_{1}I_{1}(t) ----(4)

We have to find electromotive force E₂(t) induced across the entirety of solenoid 2 by the change in current in solenoid 1, i.e.

                       E_{2} (t) = -n_{2}L\frac{d \phi_{1}}{dt} ---- (5)

substituting (4) in (5)

E_{2} (t) = -n_{2}L\frac{d }{dt}(\mu_o} \pi \rho^{2} n_{1}I_{1}(t))\\E_{2} (t) = -\pi\mu_o} \rho^{2} n_{1}n_{2}L\frac{d }{dt}I_{1}(t)

5 0
3 years ago
You need to calibrate your giant paintball bazooka, so you're fired at an angle of 60° and you find that the giant paintball spl
Alexxx [7]

Answer:

Vx = V0 cos 60 = V0 ./ 2        horizontal speed

Vy = V0 sin 69 = V0 * .866 = .866 V0   vertical speed

t = 107 / Vx = 214 / V0   time to travel 107 m

h = Vy t - 1/2 * g t*2   time to fall 1.7 m

-1.7 = .866 V0 * 214 / V0 - 4.9 * (214 / V0)^2           substituting

224400 / V0^2 = 187

V0 = (224400 / 187)^1/2 = 2=34.64 m/s

t = 214 / 34.64 = 6.178 stc

Check:    h = Vy t - 1/2 g t^2

-1.7 = .866 * 34.64 * 6.178 - 4.9 * 6.178^2

-1.7  = -1.69

5 0
3 years ago
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