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laila [671]
3 years ago
7

An object travels in a straight line for 1200 m at a velocity of 50 m/s, what is its time of travel?​

Physics
1 answer:
Crank3 years ago
5 0

Given that,

distance = d = 1200m

velocity/speed = s = 50m/s

time = t

Also,

s = d/t

And,

t = d/s

t = 1200/50

t = 120/5

t = 24

Therefore, it takes 24s to travel.

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I think it's Time and velocity.
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Aleonysh [2.5K]

Answer:

Good morning! It's D. all of the above

Explanation:

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6 0
2 years ago
Two objects were lifted by a machine.One object had a mass of 2 kilograms and was lifted at a speed of 2 m/sec.The other had a m
NikAS [45]

Answer:

While lifting two object the machine needs the different momentum for different mass object.

Explanation:

  • Momentum is the quantity of motion contained in an object. Usually it is measured by the product of mass and velocity.
  • Momentum of first mass = 2 kg × 2 m/sec = 4 kg m/sec
  • Momentum of second mass = 4 kg × 3 m/sec = 12 kg m/sec
  • So the machine requires higher mass in motion for second object ( i.e. momentum) than the first one while lifting.
7 0
3 years ago
An ac generator with peak voltage 100 volts is placed across a 10-? resistor. What is the average power dissipated?
Romashka [77]
The correct answer is: Average Power  = 500 W

Explanation:
Root-mean square voltage = Vrms = Vpeak /√2 = 100 / √2 volts
Resistance = R = 10 Ω
Average power = Pavg = (Vrms)^2<span> / R </span>= (100 * 100) / (2 * 10) = <span>500 W</span>
3 0
3 years ago
You connect a 100-resistor, a 800-mH inductor, and a 10.0-uF capacitor in series across a 60.0-Hz, 120-V (peak) source. The impe
steposvetlana [31]

Answer:

Impedance, Z = 107 ohms

Explanation:

It is given that,

Resistance, R = 100 ohms

Inductance, L=800\ mH=800\times 10^{-3}\ H=0.8\ H

Capacitance, C=10\ \mu F=10\times 10^{-6}\ F=10^{-5}\ F

Frequency, f = 60 Hz

Voltage, V = 120 V

The impedance of the circuit is given by :

Z=\sqrt{R^2+(X_C-X_L)^2}...........(1)

Where

X_C is the capacitive reactance, X_C=\dfrac{1}{2\pi fC}

X_C=\dfrac{1}{2\pi \times 60\times 10^{-5}}=265.65\ \Omega

X_L is the inductive reactance, X_L={2\pi fL}

X_L={2\pi \times 60\times 0.8}=301.59\ \Omega

So, equation (1) becomes :

Z=\sqrt{(100)^2+(265.65-301.59)^2}

Z = 106.26 ohms

or

Z = 107 ohms

So, the impedance of the circuit is 107 ohms. Hence, this is the required solution.

8 0
3 years ago
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