Answer:
i) C decreases
ii) Q remains constant
iii) E remains constant
iv) ΔV increases
Explanation:
i)
We know, capacitance is given by:
<em>In this case as the distance between the plates increases the capacitance decreases while area and permittivity of free space remains constant.</em>
ii)
As the amount of charge has nothing to do with the plate separation in case of an open circuit hence the charge Q remains constant.
iii)
Electric field between the plates is given as:
where:
charge density, 
<em>As we know that distance of plate separation cannot affect area of the plate. Charge Q and permittivity are also not affected by it, so E remains constant.</em>
iv)
- From the basic definition of voltage we know that it is the work done per unit charge to move it through a distance.
- Here we increase the distance so the work done per unit charge increases.
Answer:
<em>There is no induced current on the coil.</em>
Explanation:
Current is induced in a coil or a circuit, when there is a break of flux linkage. A break in flux linkage is caused by a changing magnetic field, and must be achieved by a relative motion between the coil and the magnet. Holding the magnet above the center of the coil will cause no changing magnetic filed since there is no relative motion between the coil and the magnet.
It will have the strongest attraction for a conductor.
–0.05 m/s
Explanation:
The total momentum of the system player+basketball must be conserved before and after the ball has been thrown.
Before throwing the ball, the total momentum of the system is zero, because can assume both the player and the basketball being at rest:
The total momentum after the ball has been thrown is instead the sum of the momenta of the the player and of the basketball:
where
is the player's mass
is the player's velocity
is the ball's mass
is the ball's velocity
For the conservation of momentum, we have
And the negative sign means that the player travels in the opposite direction to the ball.
