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Sholpan [36]
3 years ago
6

Why do you lose balance while standing on a bus often. Need a expert to answer this. Must choose if 1st 2nd or 3rd Newton Law. A

nd explain Please help.
Physics
1 answer:
yawa3891 [41]3 years ago
3 0

Answer:

The loss of balance while standing on a bus often is due:

  • <u>The third Newton law</u>.

Explanation:

The third Newton law from Latin says: <em>"Action is always opposed an equal reaction: or the two bodies on each other are always equal, and in opposite directions,"</em> which means that when a force is exercised in a direction by a body, the other body in the interaction exercises a force in the other direction. In the case of the person on the bus, when the bus makes a force forward, your body makes a force in the other direction (back), in a similar case, when the bus stops, its force in directed to the back, in that time your body make a force forward, in each case your body can lose balance because your center of gravity is directed in the same direction in which the opposite force to that of the bus moves.

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I’m pretty sure u have it right
8 0
3 years ago
What happens in the process of gravitational condensation?
Lerok [7]

Answer:

An object decreases in size due to the collision of materials. An object increases in size due to the addition of materials. Gas particles are formed from solar nebula materials.

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4 years ago
The Grand Canyon is 1800 meters deep at its deepest point. A rock is dropped from the rim above this point. Write the height of
snow_tiger [21]

Answer:

Explanation:

Given

height of grand canyon is h=1800\ m

Rock is dropped i.e. initial velocity is zero

u=0

Using Equation of motion

h=ut+\frac{1}{2}at^2

h=height

u=initial velocity

a=acceleration

t=time

here a=acceleration due to gravity

1800=0+\frac{1}{2}\times 9.8\times t^2

t^2=\frac{2\times 1800}{9.8}

t=19.166\ s

3 0
4 years ago
The removal of rock in solution by acidic rain water________​
Veronika [31]

Answer:

Solution

Explanation:

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3 0
3 years ago
Compute the size of the charge necessary for two spheres separated by 1m to be attached with the force of 1N. How many electrons
yarga [219]

Answer:

q\approx 6.6\cdot 10^{13}~electrons

Explanation:

<u>Coulomb's Law</u>

The force between two charged particles of charges q1 and q2 separated by a distance d is given by the Coulomb's Law formula:

\displaystyle F=k\frac{q_1q_2}{d^2}

Where:

k=9\cdot 10^9\ N.m^2/c^2

q1, q2 = the objects' charge

d= The distance between the objects

We know both charges are identical, i.e. q1=q2=q. This reduces the formula to:

\displaystyle F=k\frac{q^2}{d^2}

Since we know the force F=1 N and the distance d=1 m, let's find the common charge of the spheres solving for q:

\displaystyle q=\sqrt{\frac{F}{k}}\cdot d

Substituting values:

\displaystyle q=\sqrt{\frac{1}{9\cdot 10^9}}\cdot 1

q = 1.05\cdot 10^{-5}~c

This charge corresponds to a number of electrons given by the elementary charge of the electron:

q_e=1.6 \cdot 10^{-19}~c

Thus, the charge of any of the spheres is:

\displaystyle q = \frac{1.05\cdot 10^{-5}~c}{1.6 \cdot 10^{-19}~c}

\mathbf{q\approx 6.6\cdot 10^{13}~electrons}

5 0
3 years ago
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