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son4ous [18]
3 years ago
8

Why is there a minimum mass required for an object to become a star?

Physics
2 answers:
Damm [24]3 years ago
8 0
 <span>That is because for an </span>object<span> to be a </span>star<span> it has to have hydrogen fusion, and smaller </span>objects<span> cannot generate enough pressure for hydrogen</span>
ArbitrLikvidat [17]3 years ago
6 0

whereas the rocky asteroid Pallas, at 572km clearly has an irregular, non spherical shape. All rocky objects larger than Pallas (and there aren't many) are spherical.

Rock tends to be stronger than ice. Rocky objects are able to withstand their own gravity for longer than icy ones. Pallas is a reasonable cut of point. The next smaller asteroids (Vesta, Hygiea etc) are round-ish, but not in hydrostatic equilibrium. On the other hand Small, icy moons such as Miranda and Mimas are in, or close to equilibrium. Mimas has a diameter of just under 400km.

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4 years ago
The length of the assembly decreases by 0.006 in. when an axial a- force is applied by means of rigid end plates. Determine
Triss [41]

Answer:

(a) The magnitude of the applied force is (0.0001524k) Newton

(b) Corresponding stress in the steel core = (0.0001524k/area) Newton per meter square

Explanation:

(a) From Hookes law of elasticity,

Force applied = force constant (k) × compression

compression = 0.006 in = 0.006 × 0.0254 = 0.0001524 meter

Force applied = k × 0.0001524 = (0.0001524k) Newton

(b) Stress = Force applied (Newton)/area of steel core (meter square) = (0.0001524k/area) Newton per meter square

6 0
3 years ago
Type the correct answer in each box. Round your answers to the nearest hundredth.
sergey [27]

Hi there!

\large\boxed{PE = 7.35 J, \text{ }v \approx 3.13 m/s}

To find the potential energy of the ball at B, we can use the equation:

PE = mgh

Plug the given gravity, mass, and height:

PE = (1.5)(0.5)(9.8) = 7.35 J

At A, all of this potential energy is changed to kinetic energy, so we can use the following equation:

v = √2KE/m

Plug in the solved for energy and mass:

v = √2(7.35)/1.5

Solve:

v ≈ 3.13 m/s

7 0
3 years ago
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