This question is false because it is not hot or cold every single day
Mechanical and Chemical. (Weathering and erosion)
It will be then a positive ion and will be written as,
Al^3+
Answer:
(a) The magnitude of the applied force is (0.0001524k) Newton
(b) Corresponding stress in the steel core = (0.0001524k/area) Newton per meter square
Explanation:
(a) From Hookes law of elasticity,
Force applied = force constant (k) × compression
compression = 0.006 in = 0.006 × 0.0254 = 0.0001524 meter
Force applied = k × 0.0001524 = (0.0001524k) Newton
(b) Stress = Force applied (Newton)/area of steel core (meter square) = (0.0001524k/area) Newton per meter square
Hi there!
To find the potential energy of the ball at B, we can use the equation:
PE = mgh
Plug the given gravity, mass, and height:
PE = (1.5)(0.5)(9.8) = 7.35 J
At A, all of this potential energy is changed to kinetic energy, so we can use the following equation:
v = √2KE/m
Plug in the solved for energy and mass:
v = √2(7.35)/1.5
Solve:
v ≈ 3.13 m/s
