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2 years ago

Which event happens as the amplitude of a light wave increases?

Physics

2 answers:

aivan3 [116]2 years ago

8 0

Answer:

C. The light appears brighter

Explanation:

Nataliya [291]2 years ago

4 0

Answer:

Explanation:

the light. appears dimmmer

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A tall cylinder contains 30 cm of water. oil is carefully poured into the cylinder, where it floats on top of the water, until t

Art [367]

The total gauge pressure at the bottom of the cylinder would simply be the sum of the pressure exerted by water and pressure exerted by the oil.

The formula for calculating pressure in a column is:

P = ρ g h

Where,

P = gauge pressure

ρ = density of the liquid

g = gravitational acceleration

h = height of liquid

Adding the two pressures will give the total:

P total = (ρ g h)_water + (ρ g h)_oil

P total = (1000 kg / m^3) (9.8 m / s^2) (0.30 m) + (900 kg / m^3) (9.8 m / s^2) (0.4 - 0.30 m)

P total = 2940 Pa + 882 Pa

P total = 3,822 Pa

Answer:

The total gauge pressure at the bottom is 3,822 Pa.

6 0

2 years ago

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PLEASE ANSWER!!! WILL GIVE BRAINLIEST!!!!!

Kipish [7]

Answer:

the ability to do work.

EXPLAINATION: .

in other words "the potential for causing changes" or "energy is the cause of any change" or "a work that a certain force *eg: gravitational* can do.

sorry if this is not the answer that you wanted but I couldn't understand your question that's why I wrote what I understood.

6 0

2 years ago

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A car speeds past you sounding its horn at a frequency of 1000Hz. The frequency you hear:

ki77a [65]

Answer:

f' =1064.1025 Hz

Explanation:

We know that from doppler's effect

$f'=\frac{v+v_0}{v-v_s}f$

f'= observed frequency

f= actual frequency =1000 Hz

v= velocity of sound waves = 332 m/s

v_o= velocity of observer =0

v_s= velocity of source. ( let velocity of car be 20 m/s)

therefore,

$f'=\frac{332+0}{332-20}\times1000$

f' =1064.1025 Hz

3 0

2 years ago

What location is shown in the image above ? A. The Rocky Mountains B. The Sierra nevadas C. the Grand Canyon D. The Great Basin

bazaltina [42]

Answer: I’m like 99% sure that’s the Grand Canyon

Explanation:it looks like it lol

5 0

2 years ago

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A 20-lb force acts to the west while an 80-lb force acts 45° east of north. The magnitu 80 lb 70 lb 067 lb 100 lb

olga55 [171]

Answer:

The magnitude of the resulting force is 67 lbf.

Explanation:

Taking the east as the positive x direction, and the north as the positive y direction.

The first force points west, this is, in the direction of $-\hat{i}$ , so, is

$\vec{F}_1 = - 20 \ lbf \ \hat{j}$

$\vec{F}_1 = (0 , - 20 \ lbf \)$

For the second force, knowing the magnitude and directions relative to the x axis, we can find Cartesian representation of the vectors using the formula

$\ \vec{A} = | \vec{A} | \ ( \ cos(\theta) \ , \ sin (\theta) \ )$

where $| \vec{A} |$ is the magnitude of the vector and θ the angle with the positive x direction.

So, the second force is

$\vec{F}_2 = 80 \ lbf \ \ ( \ cos(45 \°) \ , \ sin (45 \°) \ )$

$\vec{F}_2 = ( \ 56.5685 \ lbf \ , \ 56.5685 \ lbf \ )$

The net force will be :

$\vec{F}_{net} = \vec{F}_1 + \vec{F}_2$

$\vec{F}_{net} = (0 , - 20 \ lbf \) + ( \ 56.5685 \ lbf \ , \ 56.5685 \ lbf \ )$

$\vec{F}_{net} = ( \ 56.5685 \ lbf \ , \ 56.5685 \ lbf \ - 20 \ lbf )$

$\vec{F}_{net} = ( \ 56.5685 \ lbf \ , \ 36.5685 \ lbf \ )$

To obtain the magnitude, we can use the Pythagorean Theorem

$|\vec{F}_{net}| = \sqrt{F_{net_x}^2 +F_{net_y}^2}$

$|\vec{F}_{net}| = \sqrt{( \ 56.5685 \ lbf \ )^2 +( \ 36.5685 \ lbf \ )^2}$

$|\vec{F}_{net}| = 67.36 \ lbf$

And this is the magnitude we are looking for.

8 0

2 years ago