Can’t see the pdf or video
I = MR^2
The Attempt at a Solution:::
I total = (3M)(0)^2 + (2M)(L/2)^2 + (M)(L)^2
I total = 3ML^2/2
It says the answer is 3ML^2/4 though.
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mark it as brainliest.... ✌✌✌
The product of (frequency) times (wavelength) is always
the same number (the speed of the wave).
So if the frequency is doubled, the wavelength has to drop to
half of what it was, in order to keep their product constant.
Answer:
Specific heat at constant pressure is = 1.005 kJ/kg.K
Specific heat at constant volume is = 0.718 kJ/kg.K
Explanation:
given data
temperature T1 = 50°C
temperature T2 = 80°C
solution
we know energy require to heat the air is express as
for constant pressure and volume
Q = m × c × ΔT ........................1
here m is mass of the gas and c is specific heat of the gas and Δ
T is change in temperature of the gas
here both Mass and temperature difference is equal and energy required is dependent on specific heat of air.
and here at constant pressure Specific heat is greater than the specific heat at constant volume,
so the amount of heat required to raise the temperature of one unit mass by one degree at constant pressure is
Specific heat at constant pressure is = 1.005 kJ/kg.K
and
Specific heat at constant volume is = 0.718 kJ/kg.K
Answer:
a) t = 11.407 s, b) x = 175.66 m, v = c) v = 30.80 m / s
Explanation:
a) This is a kinematics exercise, let's write the equation of each vehicle
car
x = x₀ + v₀ t + ½ a t²
Let's fix our reference system at the point where the car is, indicate that the car stops from rest vo = 0
x₀ = v₀ = 0
we substitute
x = ½ a t²
truck
x₂= v₀ t
v₀ = 15.4 m / s
at the point where they are, their positions are equal
½ a t² = vo t
t = 2 vo / a
calculate us
t = 2 15.4 / 2.70
t = 11.407 s
b) the distance to reach it
x = ½ to t²
x = ½ 2.70 11.407²
x = 175.66 m
c) the speed of the car is
v = vo + a t
vo = 0
v = at
v = 2.70 11.407
v = 30.80 m / s
