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Bumek [7]
3 years ago
8

The table and the graph below each show a different relationship between the same two variables, x and y:

Mathematics
1 answer:
Angelina_Jolie [31]3 years ago
7 0

Answer:

The answer is A.

Step-by-step explanation:

thats what i think

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Tonya's grandma has two pieces of cloth. She wants to estimate how much longer one piece is than the other. She will estimate to
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Answer:

10/1 then simplify

Step-by-step explanation:

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Karen measures the width of a garden plot and records that it is 44.25 meters. It's actual width is 45.5. What is the percent er
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In this question, <span>Karen measures the garden width result in 44.25 m while it's actual width is 45.5m. Then the amount of error that the Karen did would be: 45.5m-44.25m= 1.25m
The percent error would be:
</span>percent error = amount of error/ actual measurement
percent error = 1.25m/ 45.5m *100%=2.7% 
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3 years ago
Replace ​(. ) ​ with &lt;, &gt;, or = to make a true statement.
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3 years ago
A boat travels 33 miles downstream in 4 hours. The return trip takes the boat 7 hours. Find the speed of the boat in still water
Paha777 [63]

<u>Answer:</u>

Speed of the boat in still water = 6.125 miles/hour

<u>Step-by-step explanation:</u>

We are given that a boat travels 33 miles downstream in 4 hours and the return trip takes the boat 7 hours.

We are to find the speed of the boat in the still water.

Assuming S_b to be the speed of the boat in still water and S_w to be the speed of the water.

The speeds of the boat add up when the boat and water travel in the same direction.

Speed = \frac{distance}{time}

S_b+S_w=\frac{d}{t_1}=\frac{33 miles}{4 hours}

And the speed of the water is subtracted from the speed of the boat when the boat is moving upstream.

S_b-S_w=\frac{d}{t_2}=\frac{33 miles}{7 hours}

Adding the two equations to get:

   S_b+S_w=\frac{d}{t_1}

+  S_b-S_w=\frac{d}{t_2}

___________________________

2S_b=\frac{d}{t_1} +\frac{d}{t_2}

Solving this equation for S_b and substituting the given values for d,t_1, t_2:

S_b=\frac{(t_1+t_2)d}{2t_1t_2}

S_b=\frac{(4 hour + 7hour)33 mi}{2(4hour)(7hour)}

S_b=\frac{(11 hour)(33mi)}{56hour^2}

S_b=6.125 mi/hr

Therefore, the speed of the boat in still water is 6.125 miles/hour.

6 0
3 years ago
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