Answer: genotype: Ee phenotype: two small eyes.
genotype: RR' phenotype: pink eyes
genotype: GB phenotype: green and blue splotches
genotype: cc phenotype: straight
genotype: Tt phenotype: has tail
genotype: Ss phenotype: sharp teeth
genotype: FF' phenotype: three toes
genotype: ww phenotype: white
genotype: YY phenotype: pointy
genotype: nn phenotype: two ears
genotype: Ll phenotype: long
Explanation: hope this helps (the uppercase letters are dominant genes. the lowercase letter are recessive genes. for a recessive gene to show up in a phenotype you need 2 lower case letters such as cc or ss. for a dominant gene to show up in phenotype you need either 1 or 2 uppercase letters such as Cc or SS. Codominant genes present both colors in the phenotypes i.e. a brown and white cow. incomplete dominance is when neither gene is dominant so a mix of the 2 are present in the phenotype i.e. a pink rose. A regulatory gene controls the expression of a gene
<span>this is a limiting reagent problem.
first, balance the equation
4Na+ O2 ---> 2Na2O
use both the mass of Na and mass of O2 to figure out how much possible Na2O you could make.
start with Na and go to grams of Na2O
55.3 gNa x (1molNa/23.0gNa) x (2 molNa2O/4 molNa) x (62.0gNa2O/1molNa2O) = 75.5 gNa2O
do the same with O2
64.3 gO2 x (1 molO2/32.0gO2) x (2 molNa2O/1 mol O2) x (62.0gNa2O/1molNa2O) = 249.2 g Na2O
now you must pick the least amount of Na2O for the one that you actually get in the reaction. This is because you have to have both reacts still present for a reaction to occur. So after the Na runs out when it makes 75.5 gNa2O with O2, the reaction stops.
So, the mass of sodium oxide is
75.5 g</span>
40.0mL(1 L/1000 mL) = 0.040 L
<span>then plug into the formula M = moles/liters </span>
<span>0.035 M = moles/ 0.040L </span>
<span>multipy both sides by 0.040L, and you get 0.0014 moles </span>
<span>so the answer is 1</span>
A asystem at equilibrium stops
12.2 C
It has 3 significant figures now.
