5.82 760. Х 425.976 answer should have sig.figs. calculated answer:

Chemistry

1 answer:

Mekhanik [1.2K]3 years ago

7 0

Answer:

2482.4177376

Explanation:

1: 5.82 760 times 425.976

2: You will find the answer that is 2482.4177376

Hope this helps.

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When 20.4g of sodium metal are mixed with chlorine gas, are 52.0 g of sodium chloride

vagabundo [1.1K]

Answer: True

Explanation:

$\mathrm{The\ balanced \ chemical \ equation\ is\ :}\\$2 \mathrm{Na}{(s)}+\mathrm{Cl}_{2}(g) \rightarrow 2 \mathrm{NaCl}(s)$

For Na

$\\$Given mass $=20.4 \mathrm{~g}$ \ \ Molecular mass $=23 \mathrm{~g}\ \ $Number of moles $=\frac{\text { Given mass }}{\text { Molecular mass }}$$$\begin{aligned}&=\frac{20.4}{23} \\&=0.887 \text { moles }\end{aligned}$$Stoichiometric ratio of $\mathrm{Na}$ is same as that of $\mathrm{NaCl}$ i.e., $1: 1$.$\therefore$ Moles of $\mathrm{NaCl}=0.887$ motes$

For NaCl

$\\\begin{aligned}\text { Molecular mass } &=23+35.5 \\&=58.5 \mathrm{~g}\end{aligned}$

$\begin{aligned}\\& $\therefore$ Mass of $\mathrm{NaCl}$ produced will be=\text { No.of moles } \times \text { Molecular mass } \\&=0.887 \times 58.5 \\&=51.9 \\&\simeq 52 \mathrm{~g} \quad\end{aligned}$$$

Therefore, it is true that when 20.4g of sodium metal are mixed with chlorine gas, 52.0 g of sodium chloride is produced

6 0

2 years ago

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the atomic mass of chlorine is 35.45 u. is it possible for any single atom of chlorine to have a mass number of exactly 35.45? e

Allushta [10]

The mass of Cl on the periodic table is 35.45 atomic mass units. This is an average mass of the isotopes of chlorine. Most Cl atoms in nature have a relative mass of about 35 atomic mass units. Most of the remaining Cl isotopes have a relative mass of 37 atomic mass units.

The number 35.45u is the result of the natural mixture of Cl-35 and Cl-37, which produces the observed value.

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3 years ago

A 0.465 g sample of an unknown compound occupies 245 ml at 298 k and 1.22 atm. what is the molar mass of the unknown compound?

nekit [7.7K]

we can find the number of moles of gas using the ideal gas law equation

PV = nRT

where P - pressure - 1.22 atm

V - volume - 0.245 L

n - number of moles

R - gas constant - 0.08206 L.atm/mol.K

T - temperature - 298 K

substituting the values in the equation

1.22 atm x 0.245 L = n x 0.08206 L.atm/mol.K x 298 K

n = 0.0122 mol

molar mass of compound = mass present / number of moles therefore molar mass = 0.465 g / 0.0122 mol = 38.1 g/mol
the answer is d) 38.0 g/mol

6 0

3 years ago

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Please hurry!

-Dominant- [34]

Answer:

c. liquid

Explanation:

because the are not very close if the said very closely packed together it would have been a solid

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3 years ago

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