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CaHeK987 [17]
3 years ago
7

What 2 factors determine whether a collision between reactants is effective

Chemistry
1 answer:
andreyandreev [35.5K]3 years ago
4 0

Answer:

  • The kinetic energy and the orientation of the molecules.

Explanation:

As per the <em>collision theory</em>, in order for the reactants yield the products, the molecules or particles must collide with a kinetic energy greater than or equal to the activation energy, and they must collide in the right orientation for the old bonds can be broken and the new ones formed.

The particles of reactants that collide either with less kinetic energy than the needed or in a different orientation will not drive to formation of new products but will "bounce" without producing any chemical change.

This theory is in agreement with the observations that increasing the concentration of reactants increases the rate of reaction, because more collisions will be occur, such as increasing the temperature also increases the rate of reaction, because the collisions will be more energetic.

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Is decay pool or flux
mash [69]

Answer:

A single carbon pool can often have several fluxes both adding and removing carbon simultaneously. For example, the atmosphere has inflows from decomposition (CO2 released by the breakdown of organic matter), forest fires and fossil fuel combustion and outflows from plant growth and uptake by the oceans.

Explanation:

7 0
2 years ago
Put the following steps of specimen preparation and staining in order: I. Application of staining dyes II. Heat fixation III. Sm
MrRissso [65]

Answer:

Explanation:

II

3 0
3 years ago
A centimeter and millimeter differ from each other by a factor of _____ ?
Liono4ka [1.6K]



The answer is:  "10" .
_______________________________________________________________
  " A centimeter and millimeter differ from each other by a factor of "10" .
_______________________________________________________________
Note:
____________________________
100 cm = 1 m


1000 mm = 1m

____________
100 * (10) = 1000 .
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The answer is:  "10".
__________________________________________________________
  " A centimeter and millimeter differ from each other by a factor of "10".
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7 0
3 years ago
2AgNO3 + CaCl2 → 2AgCl + Ca(NO3)2
Harrizon [31]

It can be found that 337.5 g of AgCl formed from 100 g of silver nitrate and 258.4 g of AgCl from 100 g of CaCl₂.

<u>Explanation:</u>

2AgNO₃ + CaCl₂ → 2 AgCl + Ca(NO₃)₂

We have to find the amount of AgCl formed from 100 g of Silver nitrate by writing the expression.

100 g \text { of } A g N O_{3} \times \frac{2 \text { mol } A g N O_{3}}{169.87 g A g N O_{3}} \times \frac{2 \text { mol } A g C l}{1 \text { mol } A g N O_{3}} \times \frac{143.32 g A g C l}{1 \text { mol } A g C l}

= 337.5 g AgCl

In the same way, we can find the amount of silver chloride produced from 100 g of Calcium chloride.

It can be found as 258.4 g of AgCl produced from 100 g of Calcium chloride.

4 0
3 years ago
How many grams of hydrogen chloride can be produced from 1g of hydrogen and 55g of chlorine? What is the limiting reactant?
vova2212 [387]

Answer:

The limiting reactant is hydrogen, and the grams HCl produced is 36.175 g.

Explanation:

Balanced equation is 2 H + Cl2 = 2 HCl.

First thing, convert grams to moles via using molar mass.

Molar mass for hydrogen is 1.0079 g/mol. 1g x 1 mol / 1.0079 g = 0.99216 mol.

Molar mass for chlorine is 70.906 g/mol. 55g x 1 mol / 70.906 g = 0.7756748 mol.

Next, determine which is the limiting reactant - probably the fastest way to do it is just to take one of the reactants, say it's the limiting one, and calculate how much of the other reactant would be needed if that really was the limiting reactant, and then compare it to the actual moles of reactant available.

If hydrogen was the limiting reactant at 0.992 mol, you'd need .496 mol of Cl2 to complete the reaction.

If chloride was the limiting reactant at 0.776 mol, you'd need 1.55 mol of H to complete the reaction.

Comparing these numbers to the amounts we actually have available, the limiting reactant is hydrogen.

Once you've determined that, just plug in the amounts to the balanced equation to get the number of moles of HCL produced, which in this case, is just 0.992 mol.

Now, reverse the process that you took to get the moles of reactant, and you have the grams of product produced.

0.992 mol x 36.4609 g / 1 mol = 36.175 g.

7 0
3 years ago
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