If I work out rotational energy to be 102.2J which equals kg.M/s^2, and I hadn't factored time into it, would that be Joules per
1 answer:
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Answer:
Explanation:
Lamina that looks like a piece of a disk.
This is the expression as written:
Where e is considered a constant. So, for the second condition see first image. It is the upper zone.
Now, the first condition, it is the zone with red and green combination (not the only red nor only green).
So, combining the two conditions, would be the disk with the angles between π/4 and 3π/4. (third image)
Now, knowing the zone, we proceed with the integral, using polar coordinates :
Answer:
R = 33.1 m and y = 8.27 m
Explanation:
This exercise is projectile launch, let's use the scope equation to find the displacement on the X axis
R = vo2 sin 2θ / g
R = 18 2 sin (2 45) /9.8
R = 33.1 m
First let's look for the velocity components
vox = vo cos θ
voy = vo sin θ
vox = 18 cos 45
vox = 12.73 m / s
voy = 18 sin 45
voy = 12.73 m / s
To find the maximum vertical displacement, where the vertical velocity must be zero, we can use the equation
² =
² - 2 g y
0 = ² - 2 g y
y =² / 2g
y = 12.73² / (2 9.8)
y = 8.27 m