Which of the following statements is true?

What mass of O2 is needed to completely react with 500 g of Fe

Zina [86]

Answer:

solution given:

Explanation:

4Fe +3O2------------>2Fe2O3

4mole. 3mole. 2 mole

224g. 96g. 320g

we have

224 g of fe needed to react completely with 96 g of O2

500g of fe needed to react completely with

96 ×500/224=214.3g of O2

214.3g of O2 is a required answer.

8 0

2 years ago

When each of the following pairs of aqueous solutions is mixed, does a precipitation reaction occur? If so, write balanced molec

Aleks04 [339]

Yes, a precipitation process does take place here. BaCO₃ and KOH are the byproducts of this double displacement reaction, and since BaCO₃ is soluble in solution, it precipitates as a solid.

Molecular: Ba(NO₃)₂(aq) + K₂CO₃(aq) → 2K⁺(aq) + 2NO₃¯(aq) + BaCO₃(s) ⬇︎

The complete ionic reaction can be written as follows:

Ba²⁺(aq) + 2NO₃¯(aq) + 2K⁺(aq) + CO₃²¯(aq) → 2K⁺(aq) + 2NO₃¯(aq) + BaCO₃(s) ⬇︎

All the ions in solution have been written out. Now, on to the net ionic equation:

Ba²⁺(aq) + CO₃²¯(aq) → BaCO₃(s) ⬇︎

<h3>what is precipitation?</h3>

Any liquid or frozen water that condenses in the atmosphere and falls to the ground is known as precipitation. Snow, sleet, and rain are just a few of the variations. One of the three main processes that make up the global water cycle is precipitation, along with evaporation and condensation.

Water vapor in the clouds condenses into increasing-sized droplets of water, forming precipitation. Droplets fall to the Earth when they are sufficiently heavy. The water droplets may freeze to produce ice if a cloud is colder, as it would be at higher elevations. Depending on the temperature within the cloud and at the Earth's surface, these ice crystals eventually discharge to the Earth as snow, hail, or rain.

To learn more about precipitation visit:

brainly.com/question/18109776

#SPJ4

6 0

1 year ago

Show All Work For Brainliest

sattari [20]

Answer:

1) <u>16.8 L CO2</u>

Explanation:

How many liters of carbon dioxide gas will be produced when 75.0 g of calcium carbonate decomposes to form calcium oxide when at STP?

CaCO3 → CaO + CO2

Moles calcium carbonate = 75.0 grams / 100.09 g/mol

Moles calcium carbonate = 0.750 moles

For 1 mol CaCO3 we'll have 1 mol CaO and 1 mol CO2

For 0.750 moles CaCO3 we'll have 0.750 moles CO2

1 mol = 22.4 L

0.750 moles CO2 = 0.750 *22.4 L =<u> 16.8 L CO2</u>

2. Hydrogen gas reacts with 23.1 g of nitrogen gas to produce ammonia (NH3). What volume of ammonia will be produced at STP?

3H2 + N2 → 2NH3

Moles N2 = 23.1 grams / 28.0 g/mol

Moles N2 = 0.825 moles

For 3 moles H2 we need 1 mol N2 to produce 2 moles NH3

For 0.825 moles N2 we'll have 2*0.825 = 1.65 moles NH3

1 mol = 22.4 L

1.65 mol = 1.65 * 22.4 L = <u>36.96 L NH3</u>

<u />

3. Iron (III) oxide reacts with carbon monoxide to form iron and carbon dioxide. How many liters of carbon dioxide will be produced from 23.5 g of iron (III) oxide when at STP?

Fe2O3 + 3CO → 2Fe + 3CO2

Moles Fe2O3 = 23.5 grams / 159.69 g/mol

Moles Fe2O3 = 0.147 moles

For 1 mol Fe2O3 we need 3 moles CO to produce 2 moles Fe and 3 moles CO2

For 0.147 moles Fe2O3 we'll have 3*0.147 = 0.441 moles CO2

1 mol = 22.4 L

0.441 moles = 22.4 * 0.441 = <u>9.88 L CO2 </u>

<u />

4.How many liters of water vapor would be produced in the combustion of 12.5L of ethane, C2H6 at STP?

2C2H6 + 7O2 →4CO2 + 6H2O

22.4 L = 1 mol

12.5 L = 0.848 moles C2H6

For 2 moles C2H6 we need 7 moles O2 to produce 4 moles CO2 and 6 moles H2O

For 0.848 moles C2H6 we'll have 3*0.848 = 2.544 moles H2O

1 mol = 22.4 L

2.544 moles = 22.4 L * 2.544 = <u>56.99 L H2O</u>

5 0

3 years ago

What is the octet rule?

PolarNik [594]

The Octet rule is a general rule of thumb that applies to most atoms. Basically, it states that every atom wants to have eight valence electrons in its outermost electron shell.

4 0

3 years ago

Read 2 more answers

Element X had a mass of 300g and a 1/2 life of 10 years. how many grams will remain after 40 years?

kiruha [24]

<h3>Answer:</h3>

18.75 grams

<h3>Explanation:</h3>

Half-life refers to the time taken by a radioactive material to decay by half of the original mass.
In this case, the half-life of element X is 10 years, which means it takes 10 years for a given mass of the element to decay by half of its original mass.
To calculate the amount that remained after decay we use;

Remaining mass = Original mass × (1/2)^n, where n is the number of half-lives

Number of half-lives = Time for the decay ÷ Half-life

= 40 years ÷ 10 years

= 4

Therefore;

Remaining mass = 300 g × (1/2)⁴

= 300 g × 1/16

= 18.75 g

Hence, a mass of 300 g of an element X decays to 18.75 g after 40 years.

3 0

3 years ago