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nordsb [41]
3 years ago
14

According to the following reaction, how many grams of chlorine gas are required for the complete reaction of 25.5 grams of iron

?
iron (s) + chlorine (g) iron(III) chloride (s)
_____grams chlorine gas
Chemistry
1 answer:
ASHA 777 [7]3 years ago
3 0

Answer: 48.4 g of Cl_2 will be produced from 25.5 g of iron

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} Fe=\frac{25.5 g}{56g/mol}=0.455moles

The balanced chemical reaction is:

2Fe(s)+3Cl_2(g)\rightarrow 2FeCl_3(s)  

According to stoichiometry :

2 moles of Fe require  = 3 moles of Cl_2

Thus 0.455 moles of Fe will require=\frac{3}{2}\times 0.455=0.682moles  of Cl_2

Mass of Cl_2=moles\times {\text {Molar mass}}=0.682moles\times 71g/mol=48.4g

Thus 48.4 g of Cl_2 will be produced from 25.5 g of iron

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