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polet [3.4K]
3 years ago
11

g A heat exchanger is designed to is to heat 2,500 kg/h of water from 15 to 80 °C by engine oil. The configuration of the heat e

xchanger is in shell-and tube and the water is flowing through the tubes. The oil makes a single shell pass, entering at 160 °C and leaving at 90 °C, with an averaged heat transfer coefficient from the oil to the outer wall of the tubes equals 400 W/m2·K. The water flows through 11 brass tubes of 30 mm diameter with each tube making four passes through the shell. Assuming fully developed flow for the water inside the tubes, determine the tube length per pass to achieve these specified output temperatures. You may assume the tube wall thickness is negligible in the determination of overall heat transfer coefficient. (

Engineering
1 answer:
sergey [27]3 years ago
8 0

Answer:

See explaination

Explanation:

Please kindly check attachment for the step by step solution of the given problem.

The attached file gave a detailed solution of the problem.

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A 15.00 mL sample of a solution of H2SO4 of unknown concentration was titrated with 0.3200M NaOH. the titration required 21.30 m
natima [27]

Answer:

a. 0.4544 N

b. 5.112 \times 10^{-5 M}

Explanation:

For computing the normality and molarity of the acid solution first we need to do the following calculations

The balanced reaction

H_2SO_4 + 2NaOH = Na_2SO_4 + 2H_2O

NaOH\ Mass = Normality \times equivalent\ weight \times\ volume

= 0.3200 \times 40 g \times 21.30 mL \times  1L/1000mL

= 0.27264 g

NaOH\ mass = \frac{mass}{molecular\ weight}

= \frac{0.27264\ g}{40g/mol}

= 0.006816 mol

Now

Moles of H_2SO_4 needed  is

= \frac{0.006816}{2}

= 0.003408 mol

Mass\ of\ H_2SO_4 = moles \times molecular\ weight

= 0.003408\ mol \times 98g/mol

= 0.333984 g

Now based on the above calculation

a. Normality of acid is

= \frac{acid\ mass}{equivalent\ weight \times volume}

= \frac{0.333984 g}{49 \times 0.015}

= 0.4544 N

b. And, the acid solution molarity is

= \frac{moles}{Volume}

= \frac{0.003408 mol}{15\ mL \times  1L/1000\ mL}

= 0.00005112

=5.112 \times 10^{-5 M}

We simply applied the above formulas

4 0
3 years ago
A 600-MW steam power plant, which is cooled by a nearby river, has a thermal efficiency of 54 percent. Determine the rate of hea
Gennadij [26K]

Answer:

\dot Q _{L} = 511.111 MW. Heat transfer can be higher if themal efficiency is lower.

Explanation:

The heat transfer rate to the river water is calculated by this expression:

\dot Q_{L} = \dot Q_{H} - \dot W

\dot Q_{L} = (\frac{1}{\eta_{th}}-1 )\cdot \dot W\\\dot Q_{L} = (\frac{1}{0.54}-1)\cdot (600 MW)\\\dot Q _{L} = 511.111 MW

The actual heat transfer can be higher if the steam power plant reports an thermal efficiency lower than expected.

8 0
3 years ago
Match the scenario to the term it represents.
Ann [662]

Answer:

i nrfvewv

Explanation:

3 0
3 years ago
¿Qué áreas del conocimiento me pueden<br> aportar a la ejecución del proyecto?
allsm [11]

Answer:

la escuela,en casa y listo...............

8 0
3 years ago
Imagine you compare the effectiveness of four different types of stimulant to keep you awake while revising statistics using a o
Arlecino [84]

Answer:

The correct answer is At least two of the stimulants will have different effects on the mean time spent awake.

Explanation:

The null hypothesis exposed leads to consider an alternative hypothesis that differs from the behavior of the 4 stimulants. In this case it is related to the effects on patients, since in practice at least one will present differences compared to the others, influencing the sleep time of consumers.

4 0
3 years ago
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