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VashaNatasha [74]
3 years ago
10

What are the desired characteristics or values for the following parameters of an ideal amplifier?o Phase change as a function o

f the log of the frequency o Common Mode Rejection Ratioo Input Resistanceo Output Resistance
Engineering
1 answer:
kvv77 [185]3 years ago
4 0

Answer and Explanation:

- Phase change as a function of the log of the frequency

The phase shift should be independent of the frequency of the input signal. It should have an Infinite bandwidth with zero phase shift

- Common Mode Rejection Ratio

An ideal amplifier has Infinite common-mode rejection ratio (CMRR). A perfect operational amplifier amplifies only the voltage difference between its two inputs, completely rejecting all voltages that are common to both.

- Input Resistance

Infinite input impedance and so, zero input current & Zero input offset voltage.

The differential input impedance of the operational amplifier is defined as the impedance between its two inputs; the common-mode input impedance is the impedance from each input to ground.

And the impedance between its inputs should be infinite.

- Output Resistance

Zero output impedance and Infinite output voltage range.

Output Resistance leads to voltage drop. Thee voltage drop across the output impedance effectively reduces the open loop gain. So, the optimal value for this should be zero.

N.B - For AC circuits such as this one being discussed, resistance is known as impedance.

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soldier1979 [14.2K]

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<u>Explanation:</u>

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4 0
3 years ago
The vertical and horizontal poles at the traffic-light assembly are erected first. Determine the additional force and moment rea
konstantin123 [22]

Answer:

1. Az=258 lb

2. My=3440 ft lb

3. ∑Mz= 0

Explanation:

∑ Fx= Ax=0

∑ Fy= Ay=0

∑ Fz= Az-86-86-86

Az=258 lb

∑Mx=86 X 31 +Mx=0

Mx=2666 ft lb

∑My=86 X 40 +My=0

My=3440 ft lb

∑Mz= 0

6 0
3 years ago
Problem 1: A catchment has the following Horton’s infiltration parameters: f0=280 mm/hr, fc=25 mm/hr and k = 2.5 hr-1 . For the
harkovskaia [24]

Answer:

Ponding will occur in 40mins

Explanation:

We say that the infiltration rate is the velocity or speed at which water enters into the soil. This often times is measured by the depth (in mm) of the water layer that can enter the soil in one hour. An infiltration rate of 15 mm/hour means that a water layer of 15 mm on the soil surface, will take one hour to infiltrate.

Consider checking attachment for the step by step solution.

6 0
3 years ago
A vertical piston-cylinder device initially contains 0.2 m3 of air at 20°C. The mass of the piston is such that it maintains a c
Ann [662]

Answer:

Amount of air left in the cylinder=m_{2}=0.357 Kg

The amount of heat transfer=Q=0

Explanation:

Given

Initial pressure=P1=300 KPa

Initial volume=V1=0.2m^{3}

Initial temperature=T_{1}=20 C

Final Volume=V_{2}=0.1 m^{3}

Using gas equation

m_{1}=((P_{1}*V_{1})/(R*T_{1}))

m1==(300*0.2)/(.287*293)

m1=0.714 Kg

Similarly

m2=(P2*V2)/R*T2

m2=(300*0.1)/(0.287*293)

m2=0.357 Kg

Now calculate mass of air left,where me is the mass of air left.

me=m2-m1

me=0.715-0.357

mass of air left=me=0.357 Kg

To find heat transfer we need to apply energy balance equation.

Q=(m_{e}*h_{e})+(m_{2}*h_{2})-(m_{1}*h_{1})

Where me=m1-m2

And as the temperature remains constant,hence the enthalpy also remains constant.

h1=h2=he=h

Q=(me-(m1-m2))*h

me=m1-me

Thus heat transfer=Q=0

6 0
3 years ago
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