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VashaNatasha [74]
3 years ago
10

What are the desired characteristics or values for the following parameters of an ideal amplifier?o Phase change as a function o

f the log of the frequency o Common Mode Rejection Ratioo Input Resistanceo Output Resistance
Engineering
1 answer:
kvv77 [185]3 years ago
4 0

Answer and Explanation:

- Phase change as a function of the log of the frequency

The phase shift should be independent of the frequency of the input signal. It should have an Infinite bandwidth with zero phase shift

- Common Mode Rejection Ratio

An ideal amplifier has Infinite common-mode rejection ratio (CMRR). A perfect operational amplifier amplifies only the voltage difference between its two inputs, completely rejecting all voltages that are common to both.

- Input Resistance

Infinite input impedance and so, zero input current & Zero input offset voltage.

The differential input impedance of the operational amplifier is defined as the impedance between its two inputs; the common-mode input impedance is the impedance from each input to ground.

And the impedance between its inputs should be infinite.

- Output Resistance

Zero output impedance and Infinite output voltage range.

Output Resistance leads to voltage drop. Thee voltage drop across the output impedance effectively reduces the open loop gain. So, the optimal value for this should be zero.

N.B - For AC circuits such as this one being discussed, resistance is known as impedance.

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Primary mental skills needed for riding a motorcycle
Irina-Kira [14]

Answer:

You have to know the basic mechanics to help you correctly use the motorcycle, and you also have to have the right mindset - knowing you can ride it, and having determination. All of these factors are the primary mental skills you need for riding a motorcycle.

5 0
2 years ago
Which of the following is NOT a breach of Netiquette?
alexandr402 [8]

Answer:

I need some more point and i do not understand your question

Explanation:

7 0
2 years ago
When block C is in position xC = 0.8 m, its speed is 1.5 m/s to the right. Find the velocity of block A at this instant. Note th
Amanda [17]

Answer:

The answer is "2 m/s".

Explanation:

The triangle from of the right angle:

\to (x_c-0.8)+(1.5+y_4) +\sqrt{x_c^2 + 1.5^2}= constant

Differentiating the above equation:

\to V_c +V_A+ \frac{X_cV_c}{\sqrt{x_c^2 +1}}=0\\\\\to 1-V_A+ \frac{0.8 \times 1.5}{\sqrt{ 0.8^2+1.5}}=0\\\\

\to V_A=  \frac{1.2}{\sqrt{ 0.64+1.5}}+1\\\\

        = \frac{1.2}{ 1.46}+1\\\\= \frac{1.2+ 1.46}{ 1.46}\\\\ = \frac{2.66}{1.46}\\\\= 1.82 \ \frac{m}{s}\\\\= 2 \ \frac{m}{s}

3 0
2 years ago
Por favor. alguien me comunique con fatimalisethmateual
lions [1.4K]
Wait why do you want me to
7 0
2 years ago
Explain why it is not advisable to wear Ornament like ring at work shop​
disa [49]

The reason that it is not advisable to wear Ornament like ring at work shop​ is that rings can be easily get caught and fingers or the hands of the person can be injured, cut, scared etc.

<h3>Why should you not wear a ring at work?</h3>

Jewelry is known to bring about a lot of safety hazards for people working around chemicals and others.

Note that the reason that it is not advisable to wear Ornament like ring at work shop​ is that rings can be easily get caught and fingers or the hands of the person can be injured, cut, scared etc.

Learn more about Ornament from

brainly.com/question/24286720

#SPJ1

8 0
2 years ago
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