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2 years ago

Please help me find this equation :)

Mathematics

2 answers:

nadezda [96]2 years ago

4 0

The answer would be x=-16
2/3 x+1 = 1/6 x-7
4x+6=x-42
Multiply both sides by six to get whole numbers it makes it easier to work with.
3x=-48
Then move the x to the left of the equation away from the other numbered
X=-16
Finally divide both sides by 3 to get x alone and the answer

stira [4]2 years ago

3 0

It's -16 just use the app socratic

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The tread life of a particular brand of tire is a random variable best described by a normal distribution with a mean of 60,000

valina [46]

Answer: 61,750 miles

Step-by-step explanation:

Given : The p-value of the tires to outlast the warranty = 0.96

The probability that corresponds to 0.96 from a Normal distribution table is 1.75.

Mean : $\mu=60,000\text{ miles}$

Standard deviation : $\sigma=1000\text{ miles}$

The formula for z-score is given by : -

$z=\dfrac{x-\mu}{\sigma}\\\\\Rightarrow\ 1.75=\dfrac{x-60000}{1000}\\\\\Rightarrow\ x-60000=1750\\\\\Rightarrow\ x=61750$

Hence, the tread life of tire should be 61,750 miles if they want 96% of the tires to outlast the warranty.

3 0

3 years ago

Please help me! I will give brainly!

Viktor [21]

<h3>Answer: 0.34</h3>

============================================================

Explanation:

A = 0.61 is given to us

Pumpkin B travels 0.28 of a mile further than A does, so,

B = A+0.28 = 0.61+0.28 = 0.89

Pumpkin B travels 0.89 of a mile.

---------------------

Pumpkin C travels 0.06 of a mile more than B does, which means,

C = B + 0.06

C = 0.89 + 0.06

C = 0.95

Pumpkin C travels 0.95 of a mile.

---------------------

The last thing to do is to subtract the values of C and A

C - A = 0.95 - 0.61 = 0.34

Pumpkin C travels 0.34 of a mile further compared to pumpkin A.

---------------------

Side note: if you want to convert from miles to feet, then multiply by 5280.

For instance, 0.61 miles = 0.61*5280 = 3,220.8 feet.

5 0

3 years ago

Read 2 more answers

Let alpha and beta be conjugate complex numbers such that frac{\alpha}{\beta^2} is a real number and alpha - \beta| = 2 \sqrt{3}

miskamm [114]

Answer:

$-3+i\sqrt{3} , 1+\sqrt{3}$

Step-by-step explanation:

Given that alpha and beta be conjugate complex numbers

such that frac{\alpha}{\beta^2} is a real number and alpha - \beta| = 2 \sqrt{3}.

Let

$\alpha = x+iy\\\beta = x-iy$

since they are conjugates

$\alpha-\beta = x+iy-(x-iy)\\= 2iy= 2i\sqrt{3} \\y =\sqrt{3}$

$\frac{\alpha}{\beta^2} }\\=\frac{x+i\sqrt{3} }{(x-i\sqrt{3})^2} \\=\frac{x+i\sqrt{3}}{x^2-3-2i\sqrt{3}} \\=\frac{x+i\sqrt{3}((x^2-3+2i\sqrt{3}) }{(x^2-3-2i\sqrt{3)}(x^2-3-2i\sqrt{3})}$

Imaginary part of the above =0

i.e. $\sqrt{3} (x^2-3)+2x\sqrt{3} =0\\x^2+2x-3=0\\(x+3)(x-1) =0\\x=-3,1$

So the value of alpha = $-3+i\sqrt{3} , 1+\sqrt{3}$

3 0

3 years ago

A rectangular box has a square base with an edge length of x cm and a height of h cm. The volume of the box is given by V = x2h

creativ13 [48]

It is given in the question that

A rectangular box has a square base with an edge length of x cm and a height of h cm. The volume of the box is given by

$V = x^2h cm^3$

And the edge length of the base is 12 cm, the edge length of the base is decreasing at a rate of 2 cm/min, the height of the box is 6 cm, and the height is increasing at a rate of 1 cm/min.

Here we differentiate V with respect to t, and we use product rule, that is

$V = 2xh(dx/dt)+ x^2(dh/dt)$