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Igoryamba
3 years ago
8

What is 6.39 times 10 to the 23rd power

Physics
1 answer:
Sveta_85 [38]3 years ago
6 0

Answer:

6.39*(10 to the 23rd)=

6.39*10²³

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a particle moves along the x axis with an acceleration of a=18t, where a has units if m/s2. if the particle at time t=0 is at th
ludmilkaskok [199]

Answer:

 Position at t= 4 seconds is 144 m

Explanation:

 It is given that acceleration, a = 18 t, where t is the time.

 We know that Velocity, v = \int { a} \, dt

  Substituting value of a,

           Velocity, v = \int {18t} \, dt=\frac{18t^2}{2} +c=9t^2+c

 We know that at t = 0, v = -12 m/s

         So, 9*0^2+c=-12\\ \\ c=-12m/s

So velocity, v = (9t^2-12)m/s

  We also know that displacement, x = \int { v} \, dt

     Substituting value of v,  

        Displacement, x=\int {(9t^2-12)} \, dt=\frac{9t^3}{3} -12t+c=3t^3-12t+c

  We know that at t = 0, particle is at origin, x =0.

               So,  0=3*0^3-12*0+c\\ \\ c=0

   Displacement, x = 3t^3-12t

At t = 4 seconds

   x = 3*4^3-12*4=192--48=144m

Position at t= 4 seconds is 144 m  

4 0
3 years ago
If Siobhan hits a 0.25 kg volleyball with 0.5 N of force, what is the acceleration of the ball?
Alekssandra [29.7K]

Answer:

2 meters per second²

Explanation:

8 0
3 years ago
Read 2 more answers
How many minutes would it take a light wave to travel from the planet Venus to Earth? (Average distance from Venus to Earth = 28
Gnesinka [82]

Answer:

t=2.51min

Explanation:

The time taken by the light to travel a given distance is defined as:

t=\frac{d}{c}

Here c is obviously the speed of light. Now we convert the average distance form Venus to Earth to meters:

28*10^{6}mi*\frac{1609.34}{1mi}=4.51*10^{10}m

Finally, we calculate the minutes taken by the light to travel from Venus to Earth:

t=\frac{4.51*10^{10}m}{3*10^8\frac{m}{s}}\\t=150.33s*\frac{1min}{60s}=2.51min

6 0
3 years ago
A person can jump 1.5m on the earth. How high could the person jump on a planet having the twice the mass of the earth and twice
MrMuchimi
F=mg=Gm1m2/r^2
g=Gm2/r^2
g=2Gm2/(2r)^2=2Gm2/4r^2=Gm2/2r^2
So since there is half times the gravity on this unknown planet that has twice earth's mass and twice it's radius, then the person can jump twice as high. 1.5*2= 3m high

5 0
3 years ago
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g a horizontal wheel of radius is rotating about a vertical axis. What is the magnitude of the resultant acceleration of a bug t
mihalych1998 [28]

Answer:

   a = w² r

Explanation:

In this exercise, indicate that the wheel has angular velocity w, the worm experiences the same angular velocity if it does not move, and has an acceleration towards the center of the circle, according to Newton's second law, called the centripetal acceleration.

           a = v² / r

angular and linear variables are related

           v = w r

we substitute

          a = w² r

where r is the radius of the wheel

4 0
3 years ago
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