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Debora [2.8K]
3 years ago
15

In a well thought out and coherent paragraph, explain how stars are categorized in an HR Diagram

Physics
1 answer:
labwork [276]3 years ago
3 0

The Hertzsprung-Russell Diagram is a graphical tool that astronomers use to classify stars according to their luminosity, spectral type, color, temperature and evolutionary stage. Stars in the stable phase of hydrogen burning lie along the Main Sequence according to their mass.

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Sun *
Ludmilka [50]

Answer:

E

Explanation:

6 0
3 years ago
Determine a submarines acceleration if it's initial velocity is 9.0 m/s and it travels 1.54 km in 2 min
julia-pushkina [17]
acceleration=\frac{\Delta v}{\Delta t}\\\\ \Delta t=2min=120s\\\\s=1,54km=1540m\\\\
acceleration=\frac{v_{f}-v_{i}}{\Delta t}\\\\
\Delta v=\frac{s}{t}\\
v_{f}-v_{i}=\frac{s}{t}\\
v_{f}=\frac{1540}{120}+9=21,83\frac{m}{s}\\\\
accleration=\frac{21,83-9}{120}=\frac{12,83}{120}=\boxed{0,107\frac{m}{s}}
6 0
3 years ago
Given all the positive characteristics of Venus, why has space exploration focused so much on Mars?
Zielflug [23.3K]

The reason space exploration focused more on Mars than Venus with all the advantages, Venus still has a huge disadvantage, which is that the super hot is there and we can actually land on Venus without exploding.

6 0
4 years ago
Read 2 more answers
Which items or activities should a pregnant woman avoid to maintain her health and the health of her fetus? Check all that apply
Fynjy0 [20]

Answer:

Alcohol and drugs are a no no. you should put the answers in so people can answer correctly.

6 0
3 years ago
A one-dimensional plane wall of thickness 2l= 100 mm experiences uniform thermal energy generation of q˙= 800 w/m3 and is convec
slega [8]

Answer:

The thermal conductivity of the wall = 40W/m.C

h = 10 W/m^2.C

Explanation:

The heat conduction equation is given by:

d^2T/ dx^2 + egen/ K = 0

The thermal conductivity of the wall can be calculated using:

K = egen/ 2a = 800/2×10

K = 800/20 = 40W/m.C

Applying energy balance at the wall surface

"qL = "qconv

-K = (dT/dx)L = h (TL - Tinfinity)

The convention heat transfer coefficient will be:

h = -k × (-2aL)/ (TL - Tinfinty)

h = ( 2× 40 × 10 × 0.05) / (30-26)

h = 40/4 = 10W/m^2.C

From the given temperature distribution

t(x) = 10 (L^2-X^2) + 30 = 30°

T(L) = ( L^2- L^2) + 30 = 30°

dT/ dx = -2aL

d^2T/ dx^2 = - 2a

4 0
3 years ago
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