Answer:
electric flux through the three side = 2.35 N m²/C
Explanation:
given,
equilateral triangle of base = 25 cm
electric field strength = 260 N/C
Area of triangle = 
= 
= 0.0271 m³
electric flux = E. A
= 260 × 0.0271
= 7.046 N m²/C
since, tetrahedron does not enclose any charge so, net flux through tetrahedron is zero.
electric flux through the three side = (electric flux through base)/3
= 
electric flux through the three side = 2.35 N m²/C
Explanation:
Vnet = 0.4m/s - 3.0m/s = - 2.6m/s
so the man walks 2.6m/s towards the west
A device that does work with one movement and changes the size or direction of a force is a simple machine.
Answer:
c) What is the ratio K2/K1 of their kinetic energies?
Explanation:
Answer:
v = √ 2 G M/
Explanation:
To find the escape velocity we can use the concept of mechanical energy, where the initial point is the surface of the earth and the end point is at the maximum distance from the projectile to the Earth.
Initial
Em₀ = K + U₀
Final
= 
The kinetic energy is k = ½ m v²
The gravitational potential energy is U = - G m M / r
r is the distance measured from the center of the Earth
How energy is conserved
Em₀ = 
½ mv² - GmM /
= -GmM / r
v² = 2 G M (1 /
– 1 / r)
v = √ 2GM (1 /
– 1 / r)
The escape velocity is that necessary to take the rocket to an infinite distance (r = ∞), whereby 1 /∞ = 0
v = √ 2GM /