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vredina [299]
3 years ago
9

How many grams is 4.2X10^24 atoms of sulfur?

Chemistry
1 answer:
ipn [44]3 years ago
7 0
First find the number of moles of sulfur using dimensional analysis with avogadro’s number as the conversion factor. 4.2*10^24 atoms * (1 mol/6.022*10^23 atoms) = 7.0 mol sulfur. The molar mass of sulfur is 32.06 g/mol, which is found on the periodic table as sulfur’s (S) atomic weight. Use dimensional analysis again with the molar mass of sulfur as the conversion factor. 7.0 mol * 32.06 g/mol = 224.42 g sulfur. Since the problems gives us two significant figures, round the mass of sulfur to 220 grams, or 2.2 * 10^2 g.
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Calculate the molar mass of a gas if an 8.06×10(to the power of -2) gram sample of it occupies .0650 L at 547°C and 70.5 kPa​
notsponge [240]

Answer:

                     M.Mass = 120 g/mol

Explanation:

Data Given:

                  Volume = V = 0.0650 L

                  Temperature = T = 547 °C = 820.15 K

                  Pressure = P = 70.5 kPa = 0.695 atm

                  Gas Constant = R = 0.082057 L.atm.mol⁻¹.K⁻¹

Formula Used:

                        Assuming that the gas is ideally then according to ideal gas equation,

                                   P V = n R T

Solving for n,

                                   n = P V / R T

Putting Values,

    n = (0.695 atm × 0.0650 L) ÷ (0.082057 L.atm.mol⁻¹.K⁻¹ × 820.15 K)

    n = 6.71 × 10⁻⁴ moles

Now, Knowing that,

                                  Moles  =  Mass / M.Mass

Or,

                                  M.Mass = Mass / Moles

Putting values,

                                  M.Mass = 8.06 × 10⁻² g / 6.71 × 10⁻⁴ mol

                                  M.Mass = 120 g/mol

5 0
3 years ago
Which of the following is true regarding atomic radius?
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Hence option d is correct.
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Explanation:

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olya-2409 [2.1K]
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8 0
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