All categories

3 years ago

decide how to supersets these substances? If if is not possible, please write "cannot be separated" on the space provided

Chemistry

1 answer:

abruzzese [7]3 years ago

4 0

Answer: (although the question does not sate whether if you separate them physically or through energy. so i did both)

1. can be separated (When high-energy ultraviolet rays strike ordinary oxygen molecules (O2), they split the molecule into two single oxygen atoms, known as atomic oxygen)

2. can be separated, but through electrolysis, fiscally moving a crane to generate electricity to separate the molecules

3. Most solid particles, composed of diamagnetic or weak paramagnetic materials, cannot be extracted by a conventional magnetic separator. physically cannot be separated. but through heat yes

4. but there is a catch: doing so requires energy. ... If energy from coal were applied to drive the decomposition reaction, more CO2 would be released than consumed, because no process is perfectly efficient. so it cant be separated physically

5. it can be separated but it needs energy physically cannot be separated.

Explanation:

You might be interested in

Can someone help me please

iren [92.7K]

Answer:

Particle energy

Explanation:

5 0

3 years ago

Read 2 more answers

If 33.9g NaCl are mixed into water and the total mass is 578g, what is the CHANGE in freezing if Kb= - 1.82C/M (molal)? Assume N

steposvetlana [31]

Answer:

-1.82 °C

Explanation:

Step 1: Given data

Mass of NaCl (solute): 33.9 g

Mass of water (solvent): 578 g = 0.578 kg

Freezing point depression constant for water (Kb): -1.82 °C/m

Step 2: Calculate the molality of the solution

We will use the following expression.

m = mass of solute / molar mass of solute × kg of solvent

m = 33.9 g / 58.44 g/mol × 0.578 kg

m = 1.00 m

Step 3: Calculate the freezing point depression (ΔT)

The freezing point depression is a colligative property that, for a non-dissociated solute, can be calculated using the following expression:

ΔT = Kb × m

ΔT = -1.82 °C/m × 1.00 m

ΔT = -1.82 °C

3 0

3 years ago

A possible product created in a neutralization reaction could be:

lbvjy [14]

The answer should be H2O because it symbolises water

6 0

3 years ago

Dissolving 4.02 g of CaCl2 in enough water to make 349 mL of solution causes the temperature of the solution to increase by 3.91

gregori [183]

Answer:

ΔH per mole of CaCl2 is 160.3 kJ

Explanation:

Step 1: The balanced equation

CaCl2 (aq)→ Ca2+ + 2Cl-(aq)

Step 2: Data given

Molar mass of CaCl2 =110.98 g/mole

mass of CaCl2 = 4.02 grams

volume of the solution = 349 mL = 0.349 L

Temperature increases with 3.91 °C

Specific heat of the solution = specific hea of water = 4.18 J/°C*g

Density solution = density water = 1g/cm³

Step 3: Calculate moles of CaCl2

Numer of moles of CaCl2 = mass of CaCl2 / Molar mass of CaCl2

Number of moles = 4.02 grams /110.98 g/mole= 0.036 moles

Step 4 = Calculate amount of heat added

Q = m*c*ΔT

with m = the mass 349 grams + 4.02 grams = 353.02 grams

c = 4.18 J/°C*g

ΔT = 3.91 °C

Q = 353.02*4.18*3.91 = 5769.69 J

Step 5: Calculate ΔH per mole

5769.69 J /0.036 moles = 160269.1 J = 160.3 kJ

ΔH per mole of CaCl2 is 160.3 kJ

6 0

3 years ago

What is the boiling point of a solution produced by adding 610 g of cane sugar (molar mass 342.3 g/mol) to 1.4 kg of water? For

wel

Answer:

Boiling point of solution is $100.65^{0}\textrm{C}$

Explanation:

Cane sugar is a non-volatile solute.

According to Raoult's law for a non-volatile solute dissolved in a solution-

$\Delta T_{b}=K_{b}.m$

Where, $\Delta T_{b}$ is elivation in boiling point of solution, $K_{b}$ is ebbulioscopic constant of solvent (how much temperature is raised for dissolution of 1 mol of non-volatile solute) and m is molality of solution.