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pickupchik [31]
2 years ago
6

decide how to supersets these substances? If if is not possible, please write "cannot be separated" on the space provided​

Chemistry
1 answer:
abruzzese [7]2 years ago
4 0

Answer: (although the question does not sate whether if you separate them physically or through energy. so i did both)

1. can be separated (When high-energy ultraviolet rays strike ordinary oxygen molecules (O2), they split the molecule into two single oxygen atoms, known as atomic oxygen)

2. can be separated, but through electrolysis, fiscally moving a crane to generate electricity to separate the molecules

3. Most solid particles, composed of diamagnetic or weak paramagnetic materials, cannot be extracted by a conventional magnetic separator. physically cannot be separated. but through heat yes

4. but there is a catch: doing so requires energy. ... If energy from coal were applied to drive the decomposition reaction, more CO2 would be released than consumed, because no process is perfectly efficient. so it cant be separated physically

5. it can be separated but it needs energy physically cannot be separated.

Explanation:

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How many molecules are found in 90 grams of Al(OH)3?
jarptica [38.1K]

Answer:

6.95 x 10²³ molecules/particles

Explanation:

First we need to find the total Empirical Mass. We can find this by adding each element's mass together.

Al = 26.982,

O = 15.999

H = 1.008

26.982 + 3(15.999) + 3(1.008) = 78.003.

Now we divide by the mass given (90 grams).

90/78.003 = 1.153801777.

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6 0
3 years ago
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7 0
3 years ago
Describe how ionic compounds form crystals
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8 0
2 years ago
what temperature change will be observed if a sample of 100 g of ethylene glycol antifreeze solution (specific heat capacity = 3
ivolga24 [154]

Answer:

1°C temperature change will be observed if a sample of 100 g of ethylene glycol antifreeze solution.

Explanation:

Mass of ethylene glycol = m = 100 g

Specific heat capacity of ethylene glycol = c = 3.5 J/g°C

Change in temperature of ethylene glycol = ΔT

Heat loss by the ethylene glycol = Q = 350 J

Q=mc\Delta T

\Delta T=\frac{Q}{mc}=\frac{350 J}{100 g\times 3.5 J/g^oC}

ΔT = 1°C

1°C temperature change will be observed if a sample of 100 g of ethylene glycol antifreeze solution.

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