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pashok25 [27]
3 years ago
11

18. Which does not affect the strength of an electromagnet?

Physics
1 answer:
spayn [35]3 years ago
3 0

Answer:

<h2>The temperature does not affect the strength of a magnet</h2>

Explanation:

An electromagnet is obtained by winding an insulated wire round a soft iron rod with the wire ends connected to a DC source. such magnets have temporary magnetic properties which disappears with time as the current supply is cut off.

Furthermore the strength off an electromagnet

  1. increases as current increases
  2. increases as the number of turns increases
  3. the type of magnetic core is highly essential as an iron core will do batter than a silver core

   

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The force acting between the particles is

F=k \frac{Q_{1}Q_{2}}{r^2}
Then
Q_{2}= \frac{5.2 \times 10^-^5 \times 0.024^2}{ 9.0 \times 10^9 7.2 \times 10^-^8} =4.622 \times 10^-^1^1C




7 0
3 years ago
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A wave has a frequency of 655 he And is traveling at 455m/sec. what is the wavelength
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Answer:

v=wavelength ×f

wavelength=v/f=455/655=0.694m

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A raft with the area A , thickness= h and the mass 600 kg, Floats in still water with 7 cm
elena55 [62]

<span>In this problem, we need to solve for Bubba’s mass. To do this, we let A be the area of the raft and set the weight of the displaced fluid with the raft alone as ρwAd1g and ρwAd2g with the person on the raft, </span>where ρw is the density of water, d1 = 7cm, and d2= 8.4 cm. Set the weight of displaced fluid equal to the weight of the floating objects to eliminate A and ρw then solve for m.

<span>ρwAd1g = Mg</span>

ρw<span>Ad2g = (M + m) g</span>

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m = [(d2<span>∕d1)-1] M = [(8.4 cm/7.0 cm) - 1] (600 kg) =120 kg</span>

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7 0
4 years ago
an object is producing a sound that has a wavelength in air of 2.69m. If the speed of sound in air is 346m/s, what is the freque
Misha Larkins [42]

Answer:

129.74 Hz

Explanation:

Given:

Wave velocity ( v ) = 346 m / sec

wavelength ( λ ) = 2.69 m

We have to calculate Frequency ( f ) :

We know:

v = λ / t [ f = 1 / t ]

v = λ f

= > f = v / λ

Putting values here we get:

= > f = 346 / 2.69 Hz

= > f = 34600 / 269 Hz

= > f = 129.74 Hz

Hence, frequency of sound is 129.74 Hz.

5 0
3 years ago
a girl pushes a cart to the left with a 100-N force. A boy pushes it to the right with a 50-N force. what is the net force exert
NNADVOKAT [17]

Answer:

50 to the left

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150-100: 50 to the left

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