All categories

3 years ago

How many miles does hubble circle above our planet?

Physics

1 answer:

Lyrx [107]3 years ago

6 0

547 kilometres, or 340 miles

You might be interested in

The diagrams show objects' gravitational pull toward each

zaharov [31]

I don’t know sorry then ya soo

4 0

3 years ago

You are driving down the road at 15 m/s you step on the gas and speed up with uniform acceleration of 2.5 m/s^2 for 0.80 seconds

stepladder [879]

Answer:

$x_f = 15 m/s *0.8 s + \frac{1}{2} 2.5 m/s^2 (0.8 s)^2 = 12.8 m$

And we have the following relation between the angular displacement and the linear displacement:

$x = r \theta$

Where x represent the linear displacement and $\theta$ the angular displacement, if we solve for $\theta$ we got:

$\theta= \frac{x}{R}= \frac{12.8 m}{0.34 m}=37.65 rad$

Explanation:

For this case we have the following data given:

$v_i = 15 m/s$ represent the initial speed

$a = 2.5 m/s^2$ represent the acceleration

$t = 0.8 s$ represent the time

$R = 34 cm = 0.34 m$ represent the radius

First we can calculate the linear displacement with the following formula from kinematics:

$x_f = x_i + v_i t + \frac{1}{2} at^2$

And replacing we have:

$x_f = 15 m/s *0.8 s + \frac{1}{2} 2.5 m/s^2 (0.8 s)^2 = 12.8 m$

And we have the following relation between the angular displacement and the linear displacement:

$x = r \theta$

Where x represent the linear displacement and $\theta$ the angular displacement, if we solve for $\theta$ we got:

$\theta= \frac{x}{R}= \frac{12.8 m}{0.34 m}=37.65 rad$

And that would be the angular displacement during the period of acceleration.

5 0

3 years ago

Work occurs when

neonofarm [45]

Work occurs when an applied force results in movement of an object in the same direction as the applied force.

Work is done when a force that is applied to an object moves that object. The work is calculated by multiplying the force by the amount of movement of an object (W = F * d). A force of 10 newtons, that moves an object 3 meters, does 30 n-m of work.

6 0

4 years ago

Read 2 more answers

PLEASE HELPPP

Ksju [112]

I think the answer is C

7 0

4 years ago

Read 2 more answers

A trumpeter is placed on a moving sidewalk that moves at a constant velocity of 4.5 m/s. A listener is standing 6.0 m in front o

bearhunter [10]

You didn't actually include the speed of sound. But it doesn't matter for this question. If the trumpeter and the listener are on the same moving sidewalk then the distance between them is not changing. The Doppler shift only happens when the distance between the source and the Observer is changing. So the Listener hears the same 290 Hertz that the trumpeter is generating.

5 0

3 years ago