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Varvara68 [4.7K]
3 years ago
15

What is the caption of the compound NH4HCO3

Chemistry
1 answer:
k0ka [10]3 years ago
3 0
I think it’s Ammonium hydrogen carbonate
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To what volume in millimeters must 50.0 mL of 18.0 M H2SO4 be diluted to obtain 4.35 M H2SO4?
poizon [28]
We know that to relate solutions of with the factors of molarity and volume, we can use the equation: M_{1}  V_{1} = M_{2}  V_{2}

**NOTE: The volume as indicated in this question is defined in L, not mL, so that conversion must be made. However it is 1000 mL = 1 L.

So now we can assign values to these variables. Let us say that the 18 M H_{2}  SO_{4} is the left side of the equation. Then we have:

(18 M)(0.050 L)=(4.35M) V_{2}

We can then solve for V_{2}:

V_{2}= \frac{(18M)(0.05L)}{4.35M} and V_{2} =0.21 L or 210 mL

We now know that the total amount of volume of the 4.35 M solution will be 210 mL. This is assuming that the entirety of the 50 mL of 18 M is used and the rest (160 mL) of water is then added.


7 0
3 years ago
An industrial chemist studying bleaching and sterilizing prepares several hypochlorite buffers. Find the pH of 0.200 M HClO and
stellarik [79]

Answer:

The pH is 7.54

Explanation:

The Henderson - Hasselbalch equation states that for a buffer solution which consists of a weak acid and its conjugate base, the buffer pH is given by:

pH =pk_{a} +log(\frac{[conjugate base]}{[weakacid]})

pkₐ is for the acid

In this case, the buffer hypochlorous acid  HClO is a weak acid, and its conjugate base is the hypochlorite anion ClO⁻  is delivered to the solution via sodium hypochlorite NaClO .

NaCIO = 0.200 M

HCIO = 0.200 M

pkₐ = -log₁₀ kₐ = -log₁₀ (2.9 × 10⁻⁸) = 7.54

∴pH = =7.54 +log\frac{0.2}{0.2} = 7.54

7 0
3 years ago
What is the volume, in liters, of 7.8 x 10^25 atoms of krypton at STP?
viva [34]

Answer:

-0.758

Explanation:

7 0
3 years ago
Ex 1) 45.2 g of Zn = _____ moles Zn<br><br> Ex 2) 0.568 moles Ag = _____ grams Ag
Jlenok [28]

the molar mass of Zn is 65

  • number of mole(n)=reacting mass/molar mass
  • n=45.2/65
  • =0.70g/mol

2.the molar mass of Ag is 108

  • 0.568=m/108
  • then cross multiply
  • m=0.568×108
  • m=61.3g
5 0
2 years ago
How many atom of oxygen are in 2mole of O2​
GenaCL600 [577]

Answer:

12.044  × 10²³ atoms of oxygen

Explanation:

Given data:

Number of atoms of oxygen = ?

Moles of oxygen = 2 mol

Solution:

Avogadro number:

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.  The number 6.022 × 10²³ is called Avogadro number.

1 mole = 6.022 × 10²³ atoms of oxygen

2 mole × 6.022 × 10²³ atoms of oxygen / 1 mole

12.044  × 10²³ atoms of oxygen

3 0
3 years ago
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