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Masja [62]
3 years ago
13

How many carbon atoms are contained in 2.8 g of c2h4 ?

Chemistry
2 answers:
MrRa [10]3 years ago
8 0

Answer:

The answer to your question is:  1.205 x 10²³ atoms of Carbon

Explanation:

Data

Carbons atoms contained in 2.8 g C₂ H₄

MW C₂ H₄ = (12 x 2) + (4 x 1) = 24 + 4 = 28 g

                         28 g of C₂ H₄ ----------------  24 g of carbon

                         2.8 g C₂ H₄   -----------------    x

                         x = (2.8)(24) / (28)

                            = 2.4 grams of C

                             1 mol  -------------------   12 g of Carbon

                             x        -------------------    2.4 g

                            x = (2.4x 1) / 12 = 0.2 mol

                             1 mol -----------------   6.023 x 10 ²³ atoms

                           0.2 mol  --------------     x

                            x = (0.2 x 6.023 x 10 ²³) / 1

                              = 1.205 x 10²³ atoms

kodGreya [7K]3 years ago
8 0

Explanation:

As molar mass of C_{2}H_{4} is 28.05 g/mol and it is given that its mass is 2.8 g.

Therefore, calculate its number of moles as follows.

              No. of moles = \frac{mass}{\text{molar mass}}

                                    = \frac{2.8 g}{28.05 g/mol}

                                    = 0.099 mol

                                    = 0. 1 mol (approx)

And, according to the mole concept there are 6.022 \times 10^{23} atoms present in 1 mole of a substance.

Mathematically,    1 mole = 6.022 \times 10^{23} atoms or molecules

Therefore, calculate the number of carbon atoms present in 0.1 mol of C_{2}H_{4} as follows.

              2 \times 0.1 mol \times 6.022 \times 10^{23}}atoms /mol

                 = 1.204 \times 10^{23} atoms

Thus, we can conclude that there are 1.204 \times 10^{23} atoms of carbon atoms present in 0.1 mol of C_{2}H_{4}.

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We know,

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For , 2.41 moles of I_2 :

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We know :

\Delta S = -\dfrac{\Delta H_{rxn}}{T}\\\\\Delta S = -\dfrac{-64.78}{298}\ KJ/K\\\\\Delta S =-0.21738 \ KJ/K\\\\\Delta S=-217.38\ J/K

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7 0
3 years ago
determine the average volume from the following volume reading: 3.00ml, 2.0ml, 2.987 x 10^-3 l, and 3.4856 ml
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