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3 years ago

6

A rental car agency charges $ 220.00 per week plus $ 0.15 per mile to rent a car. How many miles can you travel in one week for

$ 355.00?

2 answers:

bazaltina [42]3 years ago

4 0

Answer:

$x=900$

Step-by-step explanation:

Read the problem carefully and figure out where it says plus and where it says per. Per implies multiplication. Plus is addition.

220+0.15x

To solve, plug in 355 for the answer and back solve for x.

$355=220+0.15x\\\mathrm{Switch\:sides}\\220+0.15x=355\\\mathrm{Multiply\:both\:sides\:by\:}100\\220\cdot \:100+0.15x\cdot \:100=355\cdot \:100\\22000+15x=35500\\\mathrm{Subtract\:}22000\mathrm{\:from\:both\:sides}\\22000+15x-22000=35500-22000\\15x=13500\\\mathrm{Divide\:both\:sides\:by\:}15\\\frac{15x}{15}=\frac{13500}{15}\\x=900\\$

kotegsom [21]3 years ago

3 0

Answer:

900

Step-by-step explanation:

math

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3 years ago

A donut store has 11 different types of donuts. You can only buy a bag of 3 of them, where each donut has to be of a different t

MakcuM [25]

Answer:

$165$ .

Step-by-step explanation:

Since repetition isn't allowed, there would be $11$ choices for the first donut, $(11 - 1) = 10$ choices for the second donut, and $(11 - 2) = 9$ choices for the third donut. If the order in which donuts are placed in the bag matters, there would be $11 \times 10 \times 9$ unique ways to choose a bag of these donuts.

In practice, donuts in the bag are mixed, and the ordering of donuts doesn't matter. The same way of counting would then count every possible mix of three donuts type $3 \times 2 \times 1 = 6$ times.

For example, if a bag includes donut of type $x$ , $y$ , and $z$ , the count $11 \times 10 \times 9$ would include the following $3 \times 2 \times 1$ arrangements:

$xyz$ .
$xzy$ .
$yxz$ .
$yzx$ .
$zxy$ .
$zyx$ .

Thus, when the order of donuts in the bag doesn't matter, it would be necessary to divide the count $11 \times 10 \times 9$ by $3 \times 2 \times 1 = 6$ to find the actual number of donut combinations:

$\begin{aligned} \frac{11 \times 10 \times 9}{3 \times 2 \times 1} = 165\end{aligned}$ .

Using combinatorics notations, the answer to this question is the same as the number of ways to choose an unordered set of $3$ objects from a set of $11$ distinct objects:

$\begin{aligned}\begin{pmatrix}11 \\ 3\end{pmatrix} &= \frac{11 !}{(11 - 3)! \times 3 !} \\ &= \frac{11 !}{8 ! \times 3 !} \\ &= \frac{11 \times 10 \times 9}{3 \times 2 \times 1} = 165\end{aligned}$ .

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2 years ago

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3 years ago

A bacteria culture starts with 100 bacteria and doubles in size every half hour.

taurus [48]

Answer:

y=25600

y=100(2)^{2t}

y=252

Step-by-step explanation:

A bacteria culture starts with 100 bacteria and doubles in size every half hour.

$y=100(2)^{2x}$

where x represents the number of hours

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Plug in 4 for t and find out the number of bacteria y

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The graph is attached below

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