Explanation:
Substances generally tends to specialize as either oxidizing or reducing agents.
An oxidizing agent is an electron acceptor which causes a co-reactant to be oxidized in a reaction.
Examples are:
Non-metals especially oxygen and the halogens.
Other examples are H₂SO₄ , HNO₃, KMnO₄, K₂Cr₂O₇
learn more:
Oxidizing and reducing agents brainly.com/question/5558762''
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Explanation:
molarity = no. of moles of solute/solution in litres
molarity =0.202/7.98
=0.025 M
-<u><em>Oxygen</em></u>
According to Google these are the percentages of the <em>Earths Atmosphere</em>
<em>1</em> 78% - Nitrogen
<u>2</u> 21% - Oxygen
<em>3</em> 0.9% - Argon
<em>4 </em>0.3 - Carbon Dioxide with very small percentage of other elements.
Answer: The balanced equation is 
.
Explanation:
The given reaction equation is as follows.
Number of atoms present on reactant side are as follows.
- Li = 1
- H = 1
= 1
Number of atoms present on product side are as follows.
- Li = 1
- H = 2
- = 1
To balance this equation, multiply Li by 2 and 
by 2 on reactant side. Also, multiply 
by 2 on product side.
Hence, the equation can be rewritten as follows.
Now, number of atoms present on reactant side are as follows.
- Li = 2
- H = 2
- = 2
Number of atoms present on product side are as follows.
- Li = 2
- H = 2
- = 2
As there are same number of atoms on both reactant and product side. Hence, the equation is now balanced.
Thus, we can conclude that the balanced equation is .
Answer:
The answer to your question is:
mass = 3.74 g
Explanation:
Data
V = (4/3) πr³
density = 1.74 g/cm³
radius = r = 0.80 cm
Process
V = (4/3) π(0.8)³ Substitution
V = 2.1446 cm³
mass = density x volume
mass = 1.74 x 2.1446 Substitution
mass = 3.74 g
I don't understand if the second section is also a question.
