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charle [14.2K]
3 years ago
7

The volume of a sphere is given by V-(4/3)r where r is the radius. The density of magnesium is 1.74 g/cm What is the mass of a m

agnesium sphere with a radius of 0.80 cm? • V= x2 m= TEMPERAURE CONVERTIONS show formulas used Convert 38.0 °F 10 °C = 3.33 (38-32)x(5/6)=3333°C Convert 23.5 °C 10 °F - 245 (22.5%6/5)+32=72.5°F SPD.
Chemistry
1 answer:
kicyunya [14]3 years ago
8 0

Answer:

The answer to your question is:

mass = 3.74 g

Explanation:

Data

V = (4/3) πr³

density = 1.74 g/cm³

radius = r = 0.80 cm

Process

V = (4/3) π(0.8)³             Substitution

V = 2.1446 cm³

mass = density x volume

mass = 1.74 x 2.1446      Substitution

mass = 3.74 g

I don't understand if the second section is also a question.

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Naddika [18.5K]

P1: 741 mmHg

V1: 3.49 L P1 x V1 / P2= (741 mmHg) (3.49 L) / 760 mmHg = 3.40 L

P2: 760 mmHg

V2: ? L

5 0
3 years ago
Plants produce a variety of substances:food,flavoring,drugs,poisons.this is a result of
tatuchka [14]

Answer:

Synthesis

Explanation:

They synthesize these chemicals

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When objects touch each other, charge can be transferred by
Dovator [93]

Answer:

friction

Explanation:

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7 0
3 years ago
A 52.0 mL portion of a 1.20 M solution is diluted to a total volume of 278 mL. A 139 mL portion of that solution is diluted by a
RoseWind [281]

Answer:

C_3=0.125M

Explanation:

Hello!

In this case, we can divide the problem in two steps:

1. Dilution to 278 mL: here, the initial concentration and volume are 1.20 M and 52.0 mL respectively, and a final volume of 278 mL, it means that the moles remain the same so we can write:

V_1C_1=V_2C_2

So we solve for C2:

C_2=\frac{C_1V_1}{V_2}=\frac{52.0mL*1.20M}{278mL}\\\\C_2=0.224M

2. Now, since 111 mL of water is added, we compute the final volume, V3:

V_3=139+111=250mL

So, the final concentration of the 139 mL portion is:

C_3=\frac{139 mL*0.224M}{250mL}\\\\C_3=0.125M

Best regards!

8 0
3 years ago
This question is about iron three of the raw material added to a blast furnace used to extract iron from henatite are coke hemat
IrinaVladis [17]

Answer: The fourth material that is added to the blast furnace is HOT AIR which provides OXYGEN for used for combustion of carbon (Coke).

Explanation:

Iron is the second most abundant metal found in the earth's crust after aluminium. It is not found in the free metallic state but are extracted from rocks which are rich in iron that contains other materials. These are known are iron ores and the most common iron ores are haematite ( Fe2O3).

Iron can be extracted from its ore with the used of blast furnace. The materials used for extraction of iron includes:

--> Coke

--> haematite( iron ore)

--> limestone and

--> Hot air.

The iron ore is first roasted in air so that iron(III)oxide is produced. The iron(III)oxide is then mixed with coke and limestone and heated to a very high temperature. Hot air is introduced into it from the bottom of the furnace. The coke is oxidizes the the oxygen in the hot air blast to liberate carbondioxide.

7 0
3 years ago
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