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ivolga24 [154]
3 years ago
13

A pendulum is swinging back and forth with no non-conservative forces acting on it. At the highest points of its trajectory, the

kinetic energy of the pendulum bob is instantaneously equal to zero joules. At the lowest point of its trajectory, the potential energy is instantaneously equal to zero joules. Which one of the following expressions describes the kinetic and potential energies at the point mid-way between to the highest and lowest points?
A. K = 0, U = Umax
B. K = U
C. K < U
D. K > U
E. U = 0, K = Kmax
Physics
1 answer:
Vesna [10]3 years ago
6 0

Answer:

K = U ( b )

Explanation:

The expression that describes the kinetic and potential energies at the point mid-way between to the highest and lowest points is  K = U

this is because at the midpoint between the highest point and the lowest point the height is expressed as( h/2) therefore potential energy at that point is expressed as m*g*h/2 therefore the remaining energy at this point will be considered the kinetic energy which will be = m*g*h/2 as well hence at midpoint Kinetic energy = potential energy

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what is the force between a 3 Coulomb charge and a 2 Coulomb charge separated by a distance of 5 meters?
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3 years ago
34. (Double points) You help your friend construct a soap box derby car for the All-American Soap Box derby's Stock Division. He
Elden [556K]

To accelerate a 34.01 kg-car at 0.55 m/s², a force of 19 N will be required, according to Newton's Second Law of Motion.

<h3>What does Newton's Second Law of Motion state?</h3>

Newton's Second Law of Motion states that acceleration (a) happens when a force (F) acts on a mass (m).

We want a car of mass 34.01 kg to have an acceleration of 0.55 m/s². We can calculate the required force using Newton's Second Law of Motion.

F = m × a = 34.01 kg × 0.55 m/s² = 19 N

To accelerate a 34.01 kg-car at 0.55 m/s², a force of 19 N will be required, according to Newton's Second Law of Motion.

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2 years ago
A ski lift has a one-way length of 1 km and a vertical rise of 200 m. The chairs are spaced 20 m apart, and each chair can seat
rusak2 [61]

Power is needed for (1) acceleration and (2) lifting the loaded chairs. These two parts can be calculated separately and then added together.

(1) Power for acceleration:

The final speed of the lift is

V=(10 km/h)(1 h×1000 m60 sec×1 km)=2.887 m/s.

Then the power needed is

Pa=12m(V2−V20)/Δt=12(50×250 kg)(2.778 m/s)2=9.6 kW.

(2) Power for lift

Assume that the acceleration is constant (i.e. power supply is constant), its value will be

a=ΔVΔt=2.778 m/s5 s=0.556 m/s2.

Then the vertical lift during acceleration will be

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Hence, the power needed to increase the potential energy of the lift is

Pg=mgΔhΔt=(50×250 kg) (9.89 m/s2)(1.36 m)/(5 s)=3.41 kW.

Then the total Power required is

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2 years ago
A locomotive is pulling 15 freight cars, each of which is loaded with the same amount of weight. The mass of each freight car (w
VMariaS [17]

Answer:

298,220 N

Explanation:

Let the force on car three is T_23-T_34

Since net force= ma

from newton's second law we have

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therefore,

T_23-T_34 = 37000×0.62

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now, we need to calculate

T_34

Notice that T_34 is accelerating all 12 cars behind 3rd car by at a rate of 0.62 m/s^2

F= ma

So, F= 12×37000×0.62= 22940×12= 275280 N

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3 0
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iogann1982 [59]

"700 watts" means 700 joules of work per second.

"300 watts" means 300 joules of work per second.

If the labels on both machines are true, and both machines
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is doing work faster than the 300-watt one.
3 0
3 years ago
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