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notka56 [123]
3 years ago
10

Nick's science class is observing the growth rate of a tomato plant. The tomato plant grows 3 cm every week for 12 weeks. What i

s the total growth of the tomato plant during these 12 weeks?
Mathematics
1 answer:
Alexandra [31]3 years ago
7 0

Answer:

36 cm

Step-by-step explanation:

Because the plant is growing the same amount each week you would take 12(3) and get 36 cm at the end of the 12 weeks.

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Does anyone know this????????
dusya [7]

Answer:

               3

       ______

    4 |       12

              -12            

              -----

                0

Step-by-step explanation:

12/4  

The top number always goes inside (larger or not), and the bottom number always goes on the outside (larger or not).

       

         ______

    4 |       12

Ask yourself how many 4's are in 12.

Let's see one 4 is just 4.

We can probably do more 4's than that.

Two 4's gives us 4+4=8.

Let's see if we can put one 4 in there.

Three 4's gives us 4+4+4=12.

So we can fit three 4's into 12 and there is nothing left over.

               3

       ______

    4 |       12

              -12                (since 4 times 3 or 4+4+4 is 12)

              -----

                0

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3 years ago
"If triangle vuw is equiangular, find k and t
balu736 [363]

The answer is b. k=64 t=52.


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Read 2 more answers
Solve 11sinθ-2=2 for a value of θ when 0≤θ≤π/2.? How do you solve the second problem?
Sergio [31]
5cos (2x)+7=cos (2x)+8, 4cos (2x)=1, cos (2x)=1/4, 2x=arccos(1/4), x=(1/2)arccos (1/4). I used x instead of theta, and arccos is cos inverse
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3 years ago
I need help with this
andre [41]

Answer:

  f(x)=\dfrac{(x+3)(x-1)^2}{(x+4)(x+3)(x-2)^2}

Step-by-step explanation:

Each vertical asymptote corresponds to a zero in the denominator. When the function does not change sign from one side of the asymptote to the other, the factor has even degree. The vertical asymptote at x=-4 corresponds to a denominator factor of (x+4). The one at x=2 corresponds to a denominator factor of (x-2)², because the function does not change sign there.

__

Each zero corresponds to a numerator factor that is zero at that point. Again, if the sign doesn't change either side of that zero, then the factor has even multiplicity. The zero at x=1 corresponds to a numerator factor of (x-1)².

__

Each "hole" in the function corresponds to numerator and denominator factors that are equal and both zero at that point. The hole at x=-3 corresponds to numerator and denominator factors of (x-3).

__

Taken altogether, these factors give us the function ...

  \boxed{f(x)=\dfrac{(x+3)(x-1)^2}{(x+4)(x+3)(x-2)^2}}

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