Answer:
3
______
4 | 12
-12
-----
0
Step-by-step explanation:
12/4
The top number always goes inside (larger or not), and the bottom number always goes on the outside (larger or not).
______
4 | 12
Ask yourself how many 4's are in 12.
Let's see one 4 is just 4.
We can probably do more 4's than that.
Two 4's gives us 4+4=8.
Let's see if we can put one 4 in there.
Three 4's gives us 4+4+4=12.
So we can fit three 4's into 12 and there is nothing left over.
3
______
4 | 12
-12 (since 4 times 3 or 4+4+4 is 12)
-----
0
The answer is b. k=64 t=52.
5cos (2x)+7=cos (2x)+8, 4cos (2x)=1, cos (2x)=1/4, 2x=arccos(1/4), x=(1/2)arccos (1/4). I used x instead of theta, and arccos is cos inverse
Answer:

Step-by-step explanation:
Each vertical asymptote corresponds to a zero in the denominator. When the function does not change sign from one side of the asymptote to the other, the factor has even degree. The vertical asymptote at x=-4 corresponds to a denominator factor of (x+4). The one at x=2 corresponds to a denominator factor of (x-2)², because the function does not change sign there.
__
Each zero corresponds to a numerator factor that is zero at that point. Again, if the sign doesn't change either side of that zero, then the factor has even multiplicity. The zero at x=1 corresponds to a numerator factor of (x-1)².
__
Each "hole" in the function corresponds to numerator and denominator factors that are equal and both zero at that point. The hole at x=-3 corresponds to numerator and denominator factors of (x-3).
__
Taken altogether, these factors give us the function ...
