f(x) = x³ - 2x² - 24x
x³ - 2x² - 24x = 0
x(x² - 2x - 24) = 0
x = 0
x² - 2x - 24 = 0
a = 1, b = -2, c = -24
Delta = (-2)² - 4 * 1 * (-24) = 4 + 96 = 100
x = (-(-2) - 10)/(2 * 1) = -8/2 = -4
x = (-(-2) + 10)/(2 * 1) = 12/2 = 6
Answer: 2)
3.45 Divided by 0.89 = a little more than 3 pounds.
X to the one third power plus x to the 2/3 power= 3
Answer:
Required volume is 
unit.
Step-by-step explanation:
Given equations of curves,
, 
substitute second in first we will get,
When 
and 
. Thus both curves intersect at the points (4,16),(-4,16). And thus 
.
Considering width of the representative rectangle as 
which is parallel to x-axis because of considering cylindrical shell. Therefore volume of the shell is given by,
Now,
Length of generating box=Length of from line x=4(axis of revolution)=circumference of the shell=(4-x)
Width of box=
Hence,
![=2\pi\{144\big[x\big]_{-4}^{4}-18\big[x^2\big]_{-4}^{4}-\frac{8}{3}\big[x^3\big]_{-4}^{4}+\frac{1}{2}\big[x^4\big]_{-4}^{4}\}](https://tex.z-dn.net/?f=%3D2%5Cpi%5C%7B144%5Cbig%5Bx%5Cbig%5D_%7B-4%7D%5E%7B4%7D-18%5Cbig%5Bx%5E2%5Cbig%5D_%7B-4%7D%5E%7B4%7D-%5Cfrac%7B8%7D%7B3%7D%5Cbig%5Bx%5E3%5Cbig%5D_%7B-4%7D%5E%7B4%7D%2B%5Cfrac%7B1%7D%7B2%7D%5Cbig%5Bx%5E4%5Cbig%5D_%7B-4%7D%5E%7B4%7D%5C%7D)
which is required volume of generating area.
