The values of the given trig functions in terms of sinθ and/or cosθ are:
sinθ = <u>tanθ.cosθ</u>
cosθ = <u>sinθ/tanθ</u>
secθ = <u>1/cosθ</u>
cscθ = <u>1/sinθ</u>
tanθ = <u>sinθ/cosθ</u>
cotθ = <u>cosθ/sinθ</u>
<h3>Trigonometric functions </h3>
From the question, we are to determine the values of the given trig functions in terms of sinθ and/or cosθ
NOTE: tanθ = sinθ / cosθ
∴ sinθ = tanθ.cosθ
From above, we can write that
cosθ = sinθ/tanθ
Secant is the <u>inverse</u> of cosine
∴ secθ = 1/cosθ
Cosecant is the <u>inverse</u> of sine
∴ cscθ = 1/sinθ
tanθ = sinθ/cosθ
Cotangent is the <u>inverse</u> of tangent
∴ cotθ = 1/tanθ
But, tanθ = sinθ/cosθ
∴ cotθ = cosθ/sinθ
Hence, the values of the given trig functions in terms of sinθ and/or cosθ are:
sinθ = <u>tanθ.cosθ</u>
cosθ = <u>sinθ/tanθ</u>
secθ = <u>1/cosθ</u>
cscθ = <u>1/sinθ</u>
tanθ = <u>sinθ/cosθ</u>
cotθ = <u>cosθ/sinθ</u>
Learn more on Trigonometric functions here: brainly.com/question/10316891
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Answer:
The missing side is 5 sq units.
Count each square unit without a grid.
The picture should prove this true that I edited.
<h3 /><h3>Proof ↓</h3>
Answer: 2.083
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first, we can find the slope from the equation that is given buy solving the equation for y
3x+2y = 6
2y = 6-3x
y = 3-3/2x
y = -3/2x+3
now that the equation is in slope-intercept form, we can easily see that the slope of the given line is -3/2
perpendicular lines have slopes that are negative reciprocals, so we can just take the negative reciprocal of the slope we have
-3/2 → 3/2 → 2/3
the slope of the perpendicular line is 2/3
hope this helped
Answer:
(0,6).
Step-by-step explanation:
Consider the standardised form of y=ax2+bx+c. Written as y=a(x2+bax)+c. xvertex=(−12)×ba → (−12)×0−1=0.
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