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grin007 [14]
3 years ago
8

Find the distance between (−7, 1) and (0, −6). Round your answer to the nearest tenth.

Mathematics
1 answer:
makkiz [27]3 years ago
6 0

Answer:

9.90

Step-by-step explanation:

a2+b2=c2

(7)2+(7)2=c2

49+49=c2

98=c2

√98=√c2

9.90=c

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QUICK PLEASE!!<br><br> -5.6 = h/5 + 12.2<br> show steps!
BaLLatris [955]

Answer: h = 89

Step-by-step explanation:  Hope correct :)

3 0
3 years ago
Read 2 more answers
What is the GCD of 18 and 48
JulijaS [17]

Answer:

6

Step-by-step explanation:

So the greatest common factor 18 and 48 is 6.

8 0
2 years ago
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Is the ans i got correct?<br>the total surface area is 33.8cm² <br>​
ElenaW [278]

Given:

A prism with height 5 cm and equilateral triangular base with side 2 cm.

To find:

The total surface area of the prism.

Solution:

Area of an equilateral triangle is:

A_1=\dfrac{\sqrt{3}}{4}a^2

Where, a is the side length.

Putting a=2, we get

A_1=\dfrac{\sqrt{3}}{4}(2)^2

A_1=\dfrac{\sqrt{3}}{4}(4)

A_1=\sqrt{3}

A_1\approx \sqrt{3}

The base and top of the prism are congruent so their area must be equal.

The lateral surface area of the prism is:

LA=Ph

Where, P is the perimeter of the base and h is the height of the prism.

The lateral surface area of the prism is:

A_2=(2+2+2)5

A_2=(6)5

A_2=30

Now, the total surface area is the sum of areas of bases and lateral surface area.

A=2A_1+A_2

A=2(1.73)+30

A=3.46+30

A=33.46

Therefore, the total surface area is 33.46 cm².

8 0
2 years ago
g The downtime per day for a computing facility has mean 4 hours and standard deviation 0.9 hour. What assumptions must be true
Sedaia [141]

Answer:

To obtain a valid approximation for probabilities about the average daily downtime, either the underlying distribution(of the downtime per day for a computing facility) must be normal, or the sample size must be of 30 or more.

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

In this question:

To obtain a valid approximation for probabilities about the average daily downtime, either the underlying distribution(of the downtime per day for a computing facility) must be normal, or the sample size must be of 30 or more.

7 0
3 years ago
Which of the following is a factor of x2 − 8x + 15?
brilliants [131]

Answer:

(x−3)(x−5)

Step-by-step explanation:

Let's factor x2−8x+15

x2−8x+15

The middle number is -8 and the last number is 15.

Factoring means we want something like

(x+_)(x+_)

Which numbers go in the blanks?

We need two numbers that...

Add together to get -8

Multiply together to get 15

Can you think of the two numbers?

Try -3 and -5:

-3+-5 = -8

-3*-5 = 15

Fill in the blanks in

(x+_)(x+_)

with -3 and -5 to get...

(x-3)(x-5)

3 0
3 years ago
Read 2 more answers
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