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sergij07 [2.7K]
3 years ago
8

If 4 x 10^21 electrons pass through a wire connected to a 15 ohm resistor in 3 s, how much electric

Physics
1 answer:
sammy [17]3 years ago
6 0

Answer:

1.) Current = 213.33A

2.) Potential difference = 3200 V

Explanation:

Given that

Number of electrons n = 4 x 10^21 electrons

Resistance R = 15 ohm

Time t = 3 s

From the definition of current ;

Current is the rate of flow of changes. That is,

Current I = Q/t

Where

Q = 4 × 10^21 × 1.6 × 10^-19

Q = 460C

Current I = 460/3

Current I = 213.33 A

Using Ohms law which state that

V = IR

Substitute the resistance R and current I into the formula above

Potential difference V = 213.3 × 15

Potential difference V = 3200 V

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Human reaction times are worsened by alcohol. How much further (in feet) would a drunk driver's car travel before he hits the br
sweet-ann [11.9K]

Answer:

A drunk driver's car travel 49.13 ft further than a sober driver's car, before it hits the brakes

Explanation:

Distance covered by the car after application of brakes, until it stops can be found by using 3rd equation of motion:

2as = Vf² - Vi²

s = (Vf² - Vi²)/2a

where,  

Vf = Final Velocity of Car = 0 mi/h

Vi = Initial Velocity of Car = 50 mi/h

a = deceleration of car  

s = distance covered

Vf, Vi and a for both drivers is same as per the question. Therefore, distance covered by both car after application of brakes will also be same.

So, the difference in distance covered occurs before application of brakes during response time. Since, the car is in uniform speed before applying brakes. Therefore, following equation shall be used:

s = vt

FOR SOBER DRIVER:

v = (50 mi/h)(1 h/ 3600 s)(5280 ft/mi) = 73.33 ft/s

t = 0.33 s

s = s₁

Therefore,

s₁ = (73.33 ft/s)(0.33 s)

s₁ = 24.2 ft

FOR DRUNK DRIVER:

v = (50 mi/h)(1 h/ 3600 s)(5280 ft/mi) = 73.33 ft/s

t = 1 s

s = s₂

Therefore,

s₂ = (73.33 ft/s)(1 s)

s₂ = 73.33 ft

Now, the distance traveled by drunk driver's car further than sober driver's car is given by:

ΔS = s₂ - s₁

ΔS = 73.33 ft - 24.2 ft

<u>ΔS = 49.13 ft</u>

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