If electromagnetic radiation acted like particles in the double-slit experiment, we would observe one bright band would appear in the center of the screen.
<h3>Bahavior of particles in double-slit experiment</h3>
In a double-slit experiment, single particles, such as photons, pass one at a time through a screen containing two slits.
The photons behave like wave and the constructive interfernce of the waves of these photons will generate a high amplitude wave seen as a bright band in the center of the screen.
Thus, if electromagnetic radiation acted like particles in the double-slit experiment, we would observe one bright band would appear in the center of the screen.
Learn more about double slit experiment here: brainly.com/question/4449144
<h2>
a) Equivalent resistance is 143 Ω</h2><h2>
b) Potential difference is 71.5 V</h2>
Explanation:
When resistors are connected in series, effective resistance is given by
Here
R₁ = 21Ω
R₂ = 58Ω
R₃ = 64Ω
a) 
Equivalent resistance is 143 Ω
b) We know
Potential difference = Current x Resistance
V = IR
I = 0.5 A
R = 143Ω
Substituting
V = 0.5 x 143 = 71.5 V
Potential difference is 71.5 V
Answer:
The solution for this problem is:
We will be using the formula for force which is F = ma
=>10,000 = 2000 * a
but we need to solve for acceleration so divide both sides by 2000, we will get:
=>a = 5 m/s^2
Let the initial velocity was u m/s
=>By v = u - at
=>0 = u - 5 x 6
Since acceleration is constant the velocity can be computed by multiplying the acceleration by 6 seconds.
=>u = 30 m/s
Explanation:
Answer:Time constant gets doubled
Explanation:
Given
L-R circuit is given and suppose R and L is the resistance and inductance of the circuit then current is given by
![i=i_0\left [ 1-e^{-\frac{t}{\tau }}\right ]](https://tex.z-dn.net/?f=i%3Di_0%5Cleft%20%5B%201-e%5E%7B-%5Cfrac%7Bt%7D%7B%5Ctau%20%7D%7D%5Cright%20%5D)
where 
is maximum current
i=current at any time
thus if inductance is doubled then time constant also gets doubled or twice to its original value.
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