4 years ago

Will someone help me will give Brainliest.

Physics

1 answer:

Stells [14]4 years ago

8 0

Answer:

1.0cm

Explanation:this is correct as 2.0-1.0=1.0 is the distance b/w two consecutive waves

plzz mark me brainliest

You might be interested in

If you exert a force of 100.0 N to lift a box a distance of 0.5 m, how much work do you do? 200 J 400 J 50 J 26 J

jeyben [28]

Work = force x distance
= 100N (force) x 0.5m (distance)
= 50J

4 0

4 years ago

Cmon Guys help your pal abigail

NemiM [27]

13-16 that is where they’re located at

8 0

3 years ago

What did Wundt's pendulum experiment demonstrate?

weeeeeb [17]

C. <span>People need time to shift between two different stimuli.</span>

6 0

3 years ago

Read 2 more answers

What is the kinetic energy of a 55 kilogram skier traveling at meters per second

Rasek [7]

How many meters per second was it traveling

4 0

4 years ago

Calculate the ratio of the drag force on a jet flying at 1190 km/h at an altitude of 7.5 km to the drag force on a prop-driven t

Bond [772]

Answer:

$\frac{D_{jet}}{D_{prop}}=2.865$

Explanation:

Given data

Speed of jet Vjet=1190 km/h

Speed of prop driven Vprop=595 km/h

Height of jet 7.5 km

Height of prop driven transport 3.8 km

Density of Air at height 10 km p7.8=0.53 kg/m³

Density of air at height 3.8 km p3.8=0.74 kg/m³

The drag force is given by:

$D=\frac{1}{2}CpAv^2\\$

The ratio between the drag force on the jet to the drag force on prop-driven transport is then given by:

$\frac{D_{jet}}{D_{prop}}=\frac{(1/2)Cp_{7.5}Av_{jet}^2}{1/2)Cp_{3.8}Av_{prop}^2} \\\frac{D_{jet}}{D_{prop}}=\frac{p_{7.5}v_{jet}^2}{p_{3.8}v_{prop}}\\\frac{D_{jet}}{D_{prop}}=\frac{(0.53)(1190)^2}{(0.74)(595)^2}\\ \frac{D_{jet}}{D_{prop}}=2.865$

4 0

3 years ago