Question

Which graph represents an odd function? There are 6 points ona coordinate plane. The points ]are (negative 5, 3), (negative 3, 1), (negative 1, 1), (1, 3), (3, negative 5), (5, negative 1). There are 8 points on a coordinate plane. The points are (negative 4, 2), (negative 3, negative 1), (negative 1, negative 3), (0, 1), (1, 0), (2, negative 4), (4, 5), (5, 4). There are 8 points on a coordinate plane. The points are (negative 4, 0), (negative 3, 1), (negative 2, negative 3), (negative 1, negative 2), (1, 2), (2, 3), (3, negative 1), (4, 0) There are 11 points on a coordinate plane. The points are (negative 4, 3), (negative 4, 4), (negative 3, 5), (negative 2, 1), (negative 1, negative 1), (0, negative 3), (1, negative 1), (2, 1), (3, 5), (4, 3), (4, 4).

Answer 1

Answer:

Option C.

Step-by-step explanation:

Let as consider f(x) is a function.

If $f(-x)=f(x)$, then f(x) is even function.

If $f(-x)=-f(x)$, then f(x) is odd function.

It means, if (x,y) is a point of the function, then (-x,-y)is also a point of the function.

In option A, (-5,3) is a point of the function, but (5,-3) is not a point of the function.

So, function in option A is not an odd function.

In option B, (-4,2) is a point of the function, but (4,-2) is not a point of the function.

So, function in option B is not an odd function.

In option C,

If (-4,0) is a point of function, then (4,0) is also the point of the function.

Similarly, (-3,1) and (3,-1), (-2,-3) and (2,3), (-1,-2) and (1,2) are points of the function.

So, function in option C is an odd function.

In option D, (-4,3) is a point of the function, but (4,-3) is not a point of the function.

So, function in option D is not an odd function.

Answer 2

Answer:

C.

Step-by-step explanation:

Just took it. Edg 2020. Hope this helps :)