Biodiversity is all ecosystems on Earth that support habitats. The ecosystem that wiuodl most likely hsve the greatest diversity woodlouse be the the jungke bevcause itb need the most baviar it need the right climate and also need s goalpost ster for sll the animals tht ;ive there.<span />
Answer:
There are approximately 1.54 moles in a 275 g sample of
.
Explanation:
To find out number of moles, fistly we have to calculate molecular mass of
.
There are 2 atoms of Potassium 1 atom of Chromium and 3 atoms of oxygen in the given compound.
For molecular mass we have to add the value of mass of 2 atoms of Potassium with mass of 1 atom of Chromium and with mass of 3 atoms of oxygen.
Atomic mass of Potassium = 39
Atomic mass of Chromium = 52
Atomic mass of Oxygen = 16
Now,
Molecular mass of
= 
The molecular mass of a compound is the mass of compound in one mole.
To find out the number of moles, we have to divide given mass of compound by its molecular mass.


Hence the number of moles in 275 gm of
is 1.54.
The molarity of the diluted solution : 1.1 M
<h3>Further explanation</h3>
Dilution is the process of adding solvent to get a more dilute solution.
The moles(n) before and after dilution are the same.
Can be formulated :

M₁ = Molarity of the solution before dilution
V₁ = volume of the solution before dilution
M₂ = Molarity of the solution after dilution
V₂ = Molarity volume of the solution after dilution
M₁=5
V₁=0.75
V₂=3.5

Hi,
Answer is 191.2.
800J = 191.2 cal
Hope this helps.
Answer: Option (B) is the correct answer.
Explanation:
Both oxygen and fluorine are period 2 elements and when we move across a period then there occurs a decrease in atomic size of the atoms. Hence, the atomic radius of a neutral fluorine atom is smaller than a neutral oxygen atom.
Moreover, atomic number of fluorine is 9 and it has higher nuclear charge due to which it will cause more attraction of electrons. As a result, size of a fluorine ion will be smaller.
On the other hand, size of oxygen atom is larger and has small nuclear charge due to which attraction of electrons by its nucleus will not be strong enough. Hence, the size of
will be larger.
Thus, we can conclude that the statement
has a larger nuclear charge than
has, is correct for the fact that the
ion is smaller than the
ion.