It's Co just look at the periodic table
V(H₂O)=500 mL
p(H₂O)=0.9982 g/mL
m(H₂O)=V(H₂O)p(H₂O)
mass of salt solution:
m=m(H₂O)+m(CuSO₄)=V(H₂O)p(H₂O)+m(CuSO₄)
w = m(CuSO₄)/m
w=m(CuSO₄)/{V(H₂O)p(H₂O)+m(CuSO₄)}
w=2.5/{500*0.9982+2.5}=0.004984 (0.4984%)
False because if the water goes below critical temp it would be frozen
Answer:
"2.48 mole" of H₂ are formed. A further explanation is provided below.
Explanation:
The given values are:
Mole of Al,
= 3.22 mole
Mole of HBr,
= 4.96 mole
Now,
(a)
The number of mole of H₂ are:
⇒ 
or,
⇒ 
⇒ 
⇒ 
(b)
The limiting reactant is:
= 
(c)
The excess reactant is:
= 
Answer:
225 mL of water must be added.
Explanation:
First we <u>calculate how many HCl moles are there in 516 mL of a 0.191 M solution</u>:
- 516 mL * 0.191 M = 98.556 mmol HCl
Now we use that number of moles (that remain constant during the <em>dilution process</em>) to <u>calculate the final volume of the 0.133 M solution</u>:
- 98.556 mmol / 0.133 M = 741 mL
We can <u>calculate the volume of water required</u> from the volume difference:
