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fgiga [73]
3 years ago
15

Water boils at 100°C at sea level. If the water in this experiment did not boil at 100°C, what could be the reason?

Chemistry
1 answer:
RSB [31]3 years ago
6 0
One reason could be that the water in this experiment, didn’t boil, but instead became a “chemical reaction” from atmospheric pressure which is normal.

While heating two different samples, of
sea level water it decides on a temperature of 102°C and the other boils at 99.2°C. Basically calculating of the percent error.
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What is the charge on an electron? –1 0 +1 +2
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Ethanol undergoes combustion in oxygen to produce carbon dioxide gas and liquid water. The standard heat of combustion of ethano
Mama L [17]

Answer:

-277.6\ \text{kJ/mol}

Explanation:

Heat of combustion of C_2H_5OH(l) = -1366.8 kJ/mol

Heat of formation of CO_2(g) = -393.5 kJ/mol

Heat of formation of H_2O(l) = -285.8 kJ/mol

The reaction is

C_2H_5OH(l)\rightarrow 2CO_2(g)+3H_2O(l)

Assuming x is the standard enthalpy of formation of ethanol

-1366.8=2\times (-393.5)+3\times (-285.8)-x\\\Rightarrow x=2\times (-393.5)+3\times (-285.8)+1366.8\\\Rightarrow x=-277.6\ \text{kJ/mol}

The standard enthalpy of formation of ethanol is -277.6\ \text{kJ/mol}.

5 0
3 years ago
Consider the following reaction: 2 Bi(s) + 3 Cl2(g) → 2 BiCl3(s)
Mandarinka [93]

Taking into account the reaction stoichiometry, 1.119 grams of chlorine gas are required to produce 3.32 grams of bismuth chloride is produced.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

2 Bi + 3 Cl₂ → 2 BiCl₃

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • Bi: 2 moles
  • Cl₂: 3 moles
  • BiCl₃: 2 moles

The molar mass of the compounds is:

  • Bi: 209 g/mole
  • Cl₂: 70.90 g/mole
  • BiCl₃: 315.45 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

Bi: 2 moles ×209 g/mole=418  g

Cl₂: 3 moles ×70.90 g/mole= 212.7 g

BiCl₃: 2 moles ×315.45 g/mole= 630.9 g

<h3>Mass of Cl₂ required</h3>

The following rule of three can be applied: If by reaction stoichiometry 630.9 grams of BiCl₃ are formed by 212.7 grams of Cl₂, 3.32 grams of BiCl₃ are formed by how much mass of Cl₂?

mass of Cl_{2} =\frac{3.32 grams of BiCl_{3}x212.7 grams of Cl_{2} }{630.9 grams of BiCl_{3}}

<u><em>mass of Cl₂= 1.119 grams</em></u>

Finally, 1.119 grams of chlorine gas are required to produce 3.32 grams of bismuth chloride is produced.

Learn more about the reaction stoichiometry:

<u>brainly.com/question/24741074</u>

<u>brainly.com/question/24653699</u>

5 0
2 years ago
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