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Radda [10]
3 years ago
15

A good hypothesis must be which of the following?

Chemistry
2 answers:
yanalaym [24]3 years ago
8 0
Testable, that is always required for a hypothesis. Otherwise, how can you prove it?
motikmotik3 years ago
4 0
Testable is the answer
hope it helps
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What does the steepness of the line on the graph represent?
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The steepness of a hill is called a slope. The same goes for the steepness of a line. The slope is defined as the ratio of the vertical change between two points, the rise, to the horizontal change between the same two points, the run.

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Which of the following correctly describes a mixture? (4 points) Group of answer choices The particles are chemically bonded tog
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The particles have no set ratio for how to combine, and they can be separated by physical means.

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5 0
3 years ago
There are several aromatic compounds with the formula C8H9Cl. Draw those that have a trisubstituted ring where the methyl groups
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Answer:

3-Chloro-1,2-dimethylbenzene

4-Chloro-1,2-dimethylbenzene

Explanation:

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7 0
4 years ago
What is the molar concentration (in moles/L) of a solution made with 3.744 g of Mg(NO3)2 dissolved in enough water to make 50.0
Annette [7]

Answer:

The molar concentration of a solution made with 3.744 g of Mg(NO₃)₂ dissolved in enough water to make 50.0 mL of solution is 0.5 \frac{moles}{L}

Explanation:

Molarity or Molar Concentration is the number of moles of solute that are dissolved in a certain volume.

The molarity of a solution is calculated by dividing the moles of the solute by the volume of the solution:

molarity=\frac{number of moles}{volume}

In this case:

  • Mg: 24.3 g/mole
  • N: 14 g/mole
  • O: 16 g/mole

So, the molar mass of Mg(NO₃)₂ is:

Mg(NO₃)₂= 24.3 g/mole + 2*(14 g/mole + 3*16 g/mole)= 148.3 g/mole

So, if you have 3.744 g of Mg(NO₃)₂, you can apply the following rule of three: if 148.3 grams of Mg(NO₃)₂ are present in 1 mole, 3.744 grams in how many moles are present?

moles=\frac{3.744 grams*1mole}{148.3 grams}

moles= 0.025

Then you have:

  • number of moles=0.025
  • volume= 50 mL= 0.05 L (being 1,000 mL= 1 L)

Replacing in the definition of molarity:

molarity=\frac{0.025 moles}{0.05 L}

you get:

molarity=0.5 \frac{moles}{L}

<u><em>The molar concentration of a solution made with 3.744 g of Mg(NO₃)₂ dissolved in enough water to make 50.0 mL of solution is </em></u>0.5 \frac{moles}{L}<u><em></em></u>

6 0
3 years ago
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