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Serjik [45]
4 years ago
15

What is hotter 6000k or 3000k

Physics
2 answers:
Maksim231197 [3]4 years ago
8 0

Answer:

6000k

Explanation:

yaroslaw [1]4 years ago
4 0

Answer:

6000k should be hotter.

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How is a pareto chart different from a standard vertical bar​ graph?
Alona [7]

Answer:

A Pareto chart, named after an Italian economist, combines a bar chart with a line graph. The bar chart is different from a histogram in more than one way. For example, the vertical bars need not touch one another as per a histogram

Explanation:

5 0
4 years ago
In a double-slit interference experiment, which of the following actions (perhaps more than one) would cause the fringe spacing
frozen [14]

Answer:

The correct option is a , c

Explanation:

Generally the  fringe spacing is mathematically defined as

        y  =  \frac{m \lambda D}{d}

Where y is the fringe spacing

           m is the order of the fringe

           \lambda is the wavelength

           D is the distance between the slit and the screen

           d is the distance between the slit

Now in order to increase the fringe spacing can do the following

  • Increase the wavelength
  • increase the distance from the slit to the screen
  • Decrease the distance between the slit          

The following action would increase the fringe spacing because the from the question these parameters are directly proportional to the fringe spacing

3 0
3 years ago
If the ice cube absorbs heat, then, heat
Rashid [163]

Answer:

<h2><em>I have no idea what any of that means </em>:'(</h2>

Explanation:

<h2><em>So Sorry. ΓΟΛ3</em></h2>
5 0
3 years ago
Does a star's apparent brightness depend only on its distance from earth?
Arisa [49]
I dont think so. It also probably matters what type of str it is
4 0
3 years ago
Read 2 more answers
A reaction has a rate constant of 0.0117 s-1 at 400.0 k and 0.689 s-1 at 450.0 k. calculate the activation energy in kilojoules
Zina [86]
By definition we have to:
 LOG (k2 / k1)=(-Ea/R)*(1/T1-1/T2)
 Where,
 k1 = 0.0117 s-1
 K2 = 0.689 s-1
 T1 = 400.0 k
 T2 = 450.0 k
 R is the ideal gas constant
 R = 8.314 KJ / (Kmol * K)
 Substituting
 ln (0.0117/0.689)=-Ea/(8.314)*((1/400)-(1/450))
 Clearing Ea:
 Ea = 122 kJ
 answer
<span> the activation energy in kilojoules for this reaction is
</span> Ea = 122 kJ
<span>
</span>
7 0
3 years ago
Read 2 more answers
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