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Umnica [9.8K]
3 years ago
14

Derivative of arcsin(cos(2x)) is this chain rule?

Physics
1 answer:
sergejj [24]3 years ago
8 0
Yes, you need to use the chain rule. Also you need to use the derivative of arcsin which is in tables.

Derivative of y = arcsin(x) = 1 / [√(1 - x^2)]

Chain rule: Derivative of archsin(cos(2x)) =

y' = 1 / [√(1 - (cos(2x))^2)] *  derivative (cos(2x) =

y' = 1 / [√(1 - (cos(2x))^2)] * (- sin (2x)) * 2

y' = -2(sin(2x)) / [√( 1 - (cos(2x))^2]



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Explanation:

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A bullet B of mass mB traveling with a speed v0 = 1400 m/s ricochets off a fixed steel plate A of mass mA. Let mA ≫ mB so that i
Greeley [361]

Answer:

Rebounce angle is 345°

Rebounce speed is 989.95m/s

Explanation:

Calculate the x  component of the velocity of the bullet before impact by using the following relation:

Vbx= Vb Cos thetha

Here,  is the initial velocity of the bullet, Vo = 1400m/s and is the incidence angle of the bullet.= theta = 15°

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Vbx = Cos15 ×1400 = 1352.30m/s

Calculate the y component using the relation:

Vby = Vo Sin theta

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Vby = 362.35m/s

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The rebound speed V' = Vby - Vbx

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V' = 989.95 m/s

5 0
4 years ago
What happens to the current supplied by the battery when you add an identical bulb in parallel to the original bulb?
Marysya12 [62]

Answer:

b. The current stays the same.

Explanation:

In the case given current is supplied by the battery to a bulb . Here, we should know that bulb also apply resistance to the flow of current .

Now, when an identical bulb is connected in parallel to the original bulb .

Therefore, both the resistance( bulb) are in parallel.

We know, when two resistance are in parallel , current through them is same and voltage is divided between them.

Therefore, in this case current stays same in the original bulb.

Hence, this is the required solution.

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