The mass will accelerate. Balanced Forces: When forces are in balance, acceleration is zero<span>. </span>
Answer:
the velocity of the point P located on the horizontal diameter of the wheel at t = 1.4 s is ![P = 104.04 \hat{i} -314.432 \hat{j}](https://tex.z-dn.net/?f=P%20%3D%20%20104.04%20%5Chat%7Bi%7D%20-314.432%20%5Chat%7Bj%7D)
Explanation:
The free-body diagram below shows the interpretation of the question; from the diagram , the wheel that is rolling in a clockwise directio will have two velocities at point P;
- the peripheral velocity that is directed downward
along the y-axis
- the linear velocity
that is directed along the x-axis
Now;
![V_x = \frac{d}{dt}(12t^3+2) = 36 t^2](https://tex.z-dn.net/?f=V_x%20%3D%20%5Cfrac%7Bd%7D%7Bdt%7D%2812t%5E3%2B2%29%20%3D%2036%20t%5E2)
![V_x = 36(1.7)^2\\\\V_x = 104.04\ ft/s](https://tex.z-dn.net/?f=V_x%20%3D%2036%281.7%29%5E2%5C%5C%5C%5CV_x%20%3D%20104.04%5C%20ft%2Fs)
Also,
![-V_y = R* \omega](https://tex.z-dn.net/?f=-V_y%20%3D%20R%2A%20%5Comega)
where
(angular velocity) = ![\frac{d\theta}{dt} = \frac{d}{dt}(8t^4)](https://tex.z-dn.net/?f=%5Cfrac%7Bd%5Ctheta%7D%7Bdt%7D%20%3D%20%5Cfrac%7Bd%7D%7Bdt%7D%288t%5E4%29)
![-V_y = 2*32t^3)\\\\\\-V_y = 2*32(1.7^3)\\\\-V_y = 314.432 \ ft/s](https://tex.z-dn.net/?f=-V_y%20%3D%202%2A32t%5E3%29%5C%5C%5C%5C%5C%5C-V_y%20%3D%202%2A32%281.7%5E3%29%5C%5C%5C%5C-V_y%20%3D%20314.432%20%5C%20ft%2Fs)
∴ the velocity of the point P located on the horizontal diameter of the wheel at t = 1.4 s is ![P = 104.04 \hat{i} -314.432 \hat{j}](https://tex.z-dn.net/?f=P%20%3D%20%20104.04%20%5Chat%7Bi%7D%20-314.432%20%5Chat%7Bj%7D)
Answer:
<em>1</em><em>. </em><em>A body is said to be at rest if its position does not change with respect to its surroundings.</em>
Answer:
Final angular velocity is 35rpm
Explanation:
Angular velocity is given by the equation:
I1w1i + I2w2i = I1w1f -I2w2f
But the two disks are identical, so Ii =I2
wf can be calculated using
wf = w1i - w2i/2
Given: w1i =50rpm w2i= 30rpm
wf= (50 + 20) / 2
wf= 70/2 = 35rpm