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1 answer:
Answer:
8.34
Explanation:
1) how much moles of NH₃ are in the reaction;
2) how much moles of H₂ are in the reaction;
3) the required mass of the H₂.
all the details are in the attachment; the answer is marked with red colour.
Note1: M(NH₃) - molar mass of the NH₃, constant; M(H₂) - the molar mass of the H₂, constant; ν(NH₃) - quantity of NH₃; ν(H₂) - quantity of H₂.
Note2: the suggested solution is not the shortest one.
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<u>Answer:</u>
<u>For a:</u> The isotopic representation of iodine is
<u>For b:</u> The isotopic representation of cesium is
<u>For c:</u> The isotopic representation of strontium is
<u>Explanation:</u>
The isotopic representation of an atom is:
where,
Z = Atomic number of the atom
A = Mass number of the atom
X = Symbol of the atom
- <u>For a:</u>
We are given:
Number of neutrons = 78
Atomic number of iodine = 53 = Number of protons
Mass number = 53 + 78 = 131
Thus, the isotopic representation of iodine is
- <u>For b:</u>
We are given:
Number of neutrons = 82
Atomic number of cesium = 55 = Number of protons
Mass number = 55 + 82 = 137
Thus, the isotopic representation of cesium is
- <u>For c:</u>
We are given:
Number of neutrons = 52
Atomic number of strontium = 38 = Number of protons
Mass number = 38 + 52 = 90
Thus, the isotopic representation of strontium is
<u>Answer:</u> The correct answer is Option 1.
<u>Explanation:</u>
Neutralization reaction is defined as the reaction in which acid reacts with a base to produce a salt along with water.
Here, HCl is an acid and is a base. When these two compounds react, the salt obtained is calcium chloride.
The equation for the above reaction is given by:
Hence, the correct answer is Option 1.