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lorasvet [3.4K]
3 years ago
8

How many significant figures are in 400..

Chemistry
2 answers:
marin [14]3 years ago
8 0

Answer:

3 significant figures are in 400..

Explanation:

Significant figures : The figures in a number which express the value -the magnitude of a quantity to a specific degree of accuracy is known as significant digits.

Rules for significant figures:

  1. Digits from 1 to 9 are always significant and have infinite number of significant figures.
  2. All non-zero numbers are always significant. For example: 654, 6.54 and 65.4 all have three significant figures.
  3. All zero’s between integers are always significant. For example: 5005, 5.005 and 50.05 all have four significant figures.
  4. All zero’s preceding the first integers are never significant. For example: 0.0078 has two significant figures.
  5. All zero’s after the decimal point are always significant. For example: 4.500, 45.00 and 450.0 all have four significant figures.
  6. In a non decimal number like 30 , there are 1 significant figure but number in which decimal is written after zero then all the zeros will become significant.

Given = 400.

As we can see that decimal point is present  after 0 which makes the all the zeros of the number significant.

So, significant figures are in 400. is 3.

Montano1993 [528]3 years ago
7 0
Answer:

There are 3 significant figures in 400.

Explanation:

All non-zero digits are significant, therefore the 4 is significant. Zeros after the number are only significant if there is a decimal point in the number, therefore the two zeros are also significant.
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Answer:

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Explanation:

Step 1: Data given

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The temperature of the metal = 75.0 °C

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The specific heat capacity of water is 4.18 J/°C*g

Step 2: Calculate the specific heat capacity of the metal

heat lost = heat gained

Q = m*c*ΔT

Qmetal = - Qwater

m(metal) * c(metal) * ΔT(metal) = m(water) * c(water) * ΔT(water)

⇒ mass of the metal = 151.5 grams

⇒ c(metal) = TO BE DETERMINED

⇒ΔT( metal) = T2 - T1 = 18.7 °C - 75.0 °C = -56.3 °C

⇒ mass of the water = 151.5 grams

⇒ c(water) = 4.184 J/g°C

⇒ ΔT(water) = 18.7° - 15.1 = 3.6 °C

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A sample of gas occupies a volume of 61.5 mL . As it expands, it does 130.1 J of work on its surroundings at a constant pressure
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Answer:

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