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blondinia [14]
3 years ago
6

The skateboarder in the drawing starts down the left side of the ramp with an initial speed of 6.4 m/s. Neglect nonconservative

forces, such as friction and air resistance, and find the height h of the highest point reached by the skateboarder on the right side of the ramp.
Physics
1 answer:
aleksandrvk [35]3 years ago
4 0

Answer:

2.087m

Explanation:

Using the formula for calculating the maximum height reached by an object expressed as:

H = u²/2g

u is the initial speed

g is the acceleration due to gravity

Given

u = 6.4m/s

g = 9.81m/s²

Substitute into the formula:

H =  6.4²/2(9.81)

H = 40.96/19.62

H = 2.087m

Hence the height h of the highest point reached by the skateboarder on the right side of the ramp is 2.087m

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Volgvan

Answer:

The rotation of a planet around it's sun

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3 years ago
Now she is out on a hike and comes to the left bank of a river. There is no bridge and the right bank is 10.0 mm away horizontal
Harrizon [31]

Answer:

a. 8.96 m/s b. 1.81 m

Explanation:

Here is the complete question.

a) A long jumper leaves the ground at 45° above the horizontal and lands 8.2 m away.

What is her "takeoff" speed  v 0 ?

b) Now she is out on a hike and comes to the left bank of a river. There is no bridge and the right bank is 10.0 m away horizontally and 2.5 m, vertically below.  

If she long jumps from the edge of the left bank at 45° with the speed calculated in part a), how long, or short, of the opposite bank will she land?

a. Since she lands 8.2 m away and leaves at an angle of 45 above the horizontal, this is a case of projectile motion. We calculate the takeoff speed v₀ from R = v₀²sin2θ/g. where R = range = 8.2 m.

So, v₀ = √gR/sin2θ = √9.8 × 8.2/sin(2×45) = √80.36/sin90 = √80.36 = 8.96 m/s.

b. We use R = v₀²sin2θ/g to calculate how long or short of the opposite bank she will land. With v₀ = 8.96 m/s and θ = 45

R = 8.96²sin(2 × 45)/9.8 = 80.2816/9.8 = 8.192 m.

So she land 8.192 m away from her bank. The distance away from the opposite bank she lands is 10 - 8.192 m = 1.808 m ≅ 1.81 m

8 0
3 years ago
What is the maximum value of the magnetic field at a distance of 2.5 m from a light bulb that radiates 100 W of single-frequency
Anvisha [2.4K]

Answer:

1.04\times 10^{-7} T

Explanation:

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r  = distance from the bulb = 2.5 m

I = Intensity of light at the location

Intensity of the light at the location is given as

I = \frac{P}{4\pi r^{2}}

I = \frac{100}{4(3.14) (2.5)^{2}}

I = 1.28 W/m²

B_{o} = maximum magnetic field

Intensity is given as

I = \frac{B_{o}^{2}c}{2\mu _{o}}

1.28 = \frac{B_{o}^{2}(3\times 10^{8})}{2(12.56\times 10^{-7})}

B_{o} = 1.04\times 10^{-7} T

7 0
3 years ago
Explain how a star's absorption spectrum and the concept of red shift help support the Big Bang Theory.
marta [7]

Answer:

Red shift supports the big bang theory. ... The light from distant galaxies is red shifted (this tells us the galaxies are moving away from us) and the further away the galaxy the greater the red shift (this tells us that the more distant the galaxy the faster it is moving). Constellations look like they are moving because earth is rotating on it's axis.

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4 0
3 years ago
Match the phrase with the term. How hard the blood pushes on the inside of the blood vessels is called . The total amount of blo
taurus [48]

Answer:

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How many times your heart beats in one minute is called ?

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The force that can put unhealthy tension on the heart as it is pumping is called ?

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The amount of blood the heart pumps out in one beat is called?

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Explanation:

4 0
3 years ago
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