it represents a physical change. it is not a chemical change because its chemical formula does not change unless combustion is involved.
the process goes like this.
1.cells
2.tissues
3.organs
4.organ systems
5.organisms
tissues are grouped to form organs.
I hope this helps.
A. The abundance of the 2nd isotope is 48.119%
B. The mass of the 2nd isotope is 108.905 amu
Let the 1st isotope be A
Let the 2nd isotope be B
A. Determination of the abundance of the 2nd isotope
Abundance of isotope A = 51.881%.
<h3>Abundance of isotope B =? </h3>
Abundance of B = 100 – A
Abundance of B = 100 – 51.881
<h3>Abundance of B = 48.119%</h3>
B. Determination of the mass of the 2nd isotope
Atomic mass of silver = 107.868 amu.
Mass of 1st isotope (A) = 106.906 amu
Abundance of isotope A (A%) = 51.881%.
Abundance of isotope B (B%) = 48.119%
<h3>Mass of 2nd isotope (B) =? </h3>
Therefore, the mass of the 2nd isotope is 108.905 amu
Learn more: brainly.com/question/7955048
hi im breanna
Answer:
The mole is simply a very large number that is used by chemists as a unit of measurement.
Explanation:
The mole is simply a very large number,
6.022
×
10
23
, that has a special property. If I have
6.022
×
10
23
hydrogen atoms, I have a mass of 1 gram of hydrogen atoms . If I have
6.022
×
10
23
H
2
molecules, I have a mass of 2 gram of hydrogen molecules. If I have
6.022
×
10
23
C
atoms, I have (approximately!) 12 grams.
The mole is thus the link between the micro world of atoms and molecules, and the macro world of grams and litres, the which we can easily measure by mass or volume. The masses for a mole of each element are given on the periodic table as the atomic weight. So, if have 12 g of
C
, I know, fairly precisely, how many atoms of carbon I have. Given this quantity, I know how many molecules of
O
2
are required to react with the
C
, which I could measure by mass or by volume.
The enthalpies of formation of each of the compound involved in the chemical reaction presented above are given below:
CO2: -393.5 kJ/mol
CO: -99 kJ/mol
O2: 0 kJ/mol
As observed O2 will not have enthalpy of formation as it is a pure substance.
To calculate for the enthalpy of reaction,
enthalpy of formation of products - enthalpy of formation of reactants
= (-99 kJ/mol) - (-393.5 kJ/mol)
= 294.5 kJ/mol
ANSWER: 294.5 kJ/mol
