Answer:
Helps eliminate waste products such as urea, uric acid ammonia, and other products via urine.
It helps maintain the osmotic level of blood and plasma.
It helps maintain the electrolyte balance in the body.
And it also helps in the metabolism of those drugs that do not get metabolized in the liver.
Explanation:
<em>"The excretory system is a passive biological system that removes excess, unnecessary materials from the body fluids of an organism, so as to help maintain internal chemical homeostasis and prevent damage to the body. The dual function of excretory systems is the elimination of the waste products of metabolism and to drain the body of used up and broken down components in a liquid and gaseous state"</em>
Answer:

Explanation:
<u>Given:</u>
Number of atoms =
atoms
Avogadro's Number =
atom / mol
<u>Required:</u>
Moles = ?
<u>Formula:</u>

<u>Solution:</u>

no. of moles = 1.55 moles
![\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AH1807</h3>
Ν= c/λ
λ= 486 nm * ( 1 m / 1x10^9 nm) = 4.86 x10^-7 m
v= (3.00 x 10^8 m/s) / (4.86 x10^-7 m)
v= 6.1728395x 10^14 s^-1
= 6.14 x10^-14 Hz
First, use the given amount of reactants to calculate the theoretical amount of products that should be formed based on stoichiometry. Next, divide the actual amount of obtained product by that theoretical amount, and multiply by 100%. This gives the percent yield of the reaction.
<u>Answer:</u> The decreasing order of
is 
<u>Explanation:</u>
The balanced equilibrium reaction for the ionization of silver bromide follows:

s s
The expression for solubility constant for this reaction will be:
![K_{sp}=[Ag^{+}][Br^-]](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D%5BAg%5E%7B%2B%7D%5D%5BBr%5E-%5D)
We are given:

Putting values in above equation, we get:

Solubility product of AgBr = 
The balanced equilibrium reaction for the ionization of silver cyanide follows:

s s
The expression for solubility constant for this reaction will be:
![K_{sp}=[Ag^{+}][CN^-]](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D%5BAg%5E%7B%2B%7D%5D%5BCN%5E-%5D)
We are given:

Putting values in above equation, we get:

Solubility product of AgCN = 
The balanced equilibrium reaction for the ionization of silver thiocyanate follows:

s s
The expression for solubility constant for this reaction will be:
![K_{sp}=[Ag^{+}][SCN^-]](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D%5BAg%5E%7B%2B%7D%5D%5BSCN%5E-%5D)
We are given:

Putting values in above equation, we get:

Solubility product of AgSCN = 
The decreasing order of
follows:
