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taurus [48]
3 years ago
14

I need help plz....​

Chemistry
2 answers:
e-lub [12.9K]3 years ago
8 0

Answer:

a. young.........................

noname [10]3 years ago
3 0

Young / Grassy

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What are three functions of the excretory system
Maru [420]

Answer:

Helps eliminate waste products such as urea, uric acid ammonia, and other products via urine.

It helps maintain the osmotic level of blood and plasma.

It helps maintain the electrolyte balance in the body.

And it also helps in the metabolism of those drugs that do not get metabolized in the liver.

Explanation:

<em>"The excretory system is a passive biological system that removes excess, unnecessary materials from the body fluids of an organism, so as to help maintain internal chemical homeostasis and prevent damage to the body. The dual function of excretory systems is the elimination of the waste products of metabolism and to drain the body of used up and broken down components in a liquid and gaseous state"</em>

5 0
3 years ago
Convert 9.32x 10 23ª atoms of au to moles of au
7nadin3 [17]

Answer:

\huge\boxed{\sf no.\ of\ moles = 1.55\ moles }

Explanation:

<u>Given:</u>

Number of atoms = 9.32 \times 10^{23} atoms

Avogadro's Number = 6.023 \times 10^{23} atom / mol

<u>Required:</u>

Moles = ?

<u>Formula:</u>

\displaystyle No.\ of\ moles = \frac{no. \ of \ atoms }{avogadro's \ no.}

<u>Solution:</u>

\displaystyle no. \ of \ moles = \frac{9.32\times 10^{23}}{6.023 \times 10^{23}}

no. of moles = 1.55 moles

\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
5 0
3 years ago
Calculate the frequency of visible light having a wavelength of 486 nm
hjlf
Ν= c/λ

λ= 486 nm * ( 1 m / 1x10^9 nm) = 4.86 x10^-7 m 

v= (3.00 x 10^8 m/s) /  (4.86 x10^-7 m) 
v= 6.1728395x 10^14 s^-1
= 6.14 x10^-14 Hz
8 0
3 years ago
Know how you would determine the percent yield of a reaction if you have the given amount of the reactants and the amount of the
Over [174]
First, use the given amount of reactants to calculate the theoretical amount of products that should be formed based on stoichiometry. Next, divide the actual amount of obtained product by that theoretical amount, and multiply by 100%. This gives the percent yield of the reaction.
5 0
4 years ago
The molar solubilities of the following compounds (in mol/L) are:
IceJOKER [234]

<u>Answer:</u> The decreasing order of K_{sp} is AgSCN>AgBr>AgCN

<u>Explanation:</u>

  • <u>For AgBr:</u>

The balanced equilibrium reaction for the ionization of silver bromide follows:

AgBr\rightleftharpoons Ag^{+}+Br^-

                 s      s

The expression for solubility constant for this reaction will be:

K_{sp}=[Ag^{+}][Br^-]

We are given:

s=7.3\times 10^{-7}mol/L

Putting values in above equation, we get:

K_{sp}=s\times s\\\\K_{sp}=s^2\\\\K_{sp}=(7.3\times 10{-7})^2=5.33\times 10^{-13}

Solubility product of AgBr = 5.33\times 10^{-13}

  • <u>For AgCN:</u>

The balanced equilibrium reaction for the ionization of silver cyanide follows:

AgCN\rightleftharpoons Ag^{+}+CN^-

                    s      s

The expression for solubility constant for this reaction will be:

K_{sp}=[Ag^{+}][CN^-]

We are given:

s=7.7\times 10^{-9}mol/L

Putting values in above equation, we get:

K_{sp}=s\times s\\\\K_{sp}=s^2\\\\K_{sp}=(7.7\times 10{-9})^2=5.93\times 10^{-17}

Solubility product of AgCN = 5.33\times 10^{-17}

  • <u>For AgSCN:</u>

The balanced equilibrium reaction for the ionization of silver thiocyanate follows:

AgSCN\rightleftharpoons Ag^{+}+SCN^-

                     s      s

The expression for solubility constant for this reaction will be:

K_{sp}=[Ag^{+}][SCN^-]

We are given:

s=1.0\times 10^{-6}mol/L

Putting values in above equation, we get:

K_{sp}=s\times s\\\\K_{sp}=s^2\\\\K_{sp}=(1.0\times 10{-6})^2=1.0\times 10^{-12}

Solubility product of AgSCN = 1.0\times 10^{-12}

The decreasing order of K_{sp} follows:

AgSCN>AgBr>AgCN

4 0
4 years ago
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