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2 years ago

I need help plz....

Chemistry

2 answers:

e-lub [12.9K]2 years ago

8 0

Answer:

a. young.........................

noname [10]2 years ago

3 0

Young / Grassy

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Balance the equation for magnasuin and oxygen to yield magnasuimoxide

Minchanka [31]

Answer:

2Mg + O₂ → 2MgO

Explanation:

Chemical equation:

Mg + O₂ → MgO

Balanced chemical equation:

2Mg + O₂ → 2MgO

The balanced equation s given above and it completely follow the law of conservation of mass.

Law of conservation of mass:

According to the law of conservation mass, mass can neither be created nor destroyed in a chemical equation.

This law was given by french chemist Antoine Lavoisier in 1789. According to this law mass of reactant and mass of product must be equal, because masses are not created or destroyed in a chemical reaction.

Steps to balanced the equation:

Step 1:

Mg + O₂ → MgO

Mg = 1 Mg = 1

O = 2 O = 1

Step 2:

2Mg + O₂ → MgO

Mg = 2 Mg = 1

O = 2 O = 1

Step 3:

2Mg + O₂ → 2MgO

Mg = 2 Mg = 2

O = 2 O = 2

6 0

2 years ago

If the molecule C6H12 does not contain a double bond, and there are no branches in it, what will its structure look like?

NARA [144]

I have attached a photo of the structure.
You can get better at solving problems like this by practicing a lot!

5 0

2 years ago

Balance the equation AlCl3 + H2SO4 yields Al2(SO4)3 +HCl

Natalija [7]

Answer:

2AlCl3 + 3H2SO4 → Al2(SO4)3 + 6HCl

Explanation:

3 0

2 years ago

Write the balanced equation. Then calculate the volume of 0.65 M HCl required to completely neutralize 400.0 ml of 0.88 M KOH.

Misha Larkins [42]

Hello!

The balanced equation for the neutralization of KOH is the following:

HCl(aq) + KOH(aq) → KCl(aq) + H₂O(l)

To calculate the volume of HCl required, we can apply the following equation:

$moles HCl = moles KOH \\ \\ cHCl*vHCl=cKOH*vKOH \\ \\ vHCl= \frac{cKOH*vKOH}{cHCl}= \frac{400 mL*0,88M}{0,65M}= 541,54mL$

So, the required volume of HCl is 541,54 mL

Have a nice day!

8 0

2 years ago

What is the molar mass for Agno3

Aloiza [94]

Answer:

169.87 g/mol

Explanation:

5 0

2 years ago

I need help plz....​

I need help plz....