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Colt1911 [192]
3 years ago
12

Which of the following solutions will have the highest concentration of chloride ions?

Chemistry
1 answer:
Mnenie [13.5K]3 years ago
4 0

Answer:

B = 0.10 M of AlCl₃

Explanation:

A = 0.10 M NaCl

NaCl → Na⁺ + Cl⁻

sodium chloride dissociate into sodium and chlorine ions. The one mole of NaCl produced on mole of Na⁺ and one mole of Cl⁻, so concentration of chloride ions will be 0.10 M.

B = 0.10 M of AlCl₃

AlCl₃  →    Al³⁺ + 3Cl⁻

AlCl₃ dissociate into aluminium cation and chlorine anion. one mole of AlCl₃ dissociate into one mole of Al³⁺ and three mole of Cl⁻.

so concentration of chloride ion in 0.10 M solution is

0.10 × 3 = 0.3 M

C = 0.10 M MgCl₂

MgCl₂   → Mg²⁺ +  2Cl⁻

MgCl₂ dissociate into one mole of Mg²⁺ and two mole of Cl⁻.

so concentration of chloride ions in 0.10 M solution of MgCl₂ is,

2× 0.10 M = 0.20 M

d = 0.05 M CaCl₂  

CaCl₂  →   Ca²⁺ +  2Cl⁻

CaCl₂ dissociate into one mole of  Ca²⁺ and two mole of Cl⁻, So concentration of chloride ions in 0.05 M CaCl₂ is

2× 0.05 = 0.1 M

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Answer:

0.0253 M/s

Explanation:

From the reaction

N₂ + 3H₂ → 2NH₃

The rate of reaction can be written as

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From the above rate equation we can conclude that the rate of reaction of N₂ is equal to one third of the rate of reaction of H₂,

So,

Rate of reaction of molecular nitrogen = \frac{1}{3} \times 0.0759

Upon calculation, we get rate of reaction of molecular nitrogen = 0.0253 M/s

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3 years ago
How many moles of calcium (Ca) atoms are there in 77.4 g of Ca?
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Strigol is an important plant hormone that is released by crops such as rice and sugarcane. Unfortunately for these plants, stri
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The hydrogen deficiency index( HDI) of strigol is = 10

<h3>How to calculate HDI:</h3>

The hydrogen deficiency index is used to measure the number of degree of unsaturation of an organic compound.

Strigol is an example of an organic compound because it contains carbons and hydrogen.

To calculate the HDI using the molecular formula given (C19H20O6) the formula for HDI is used which is:

hdi =  \frac{1}{2} (2c + 2 + n - h - x)

where C = number of carbon atoms = 19

n= number of nitrogen atoms = 0

h= number of hydrogen atoms = 20

X = number of halogen atoms = 0

Note that oxygen was not considered because it forms two bonds and has no impact.

There for HDI =

\frac{1}{2} (2 \times 19 + 2 + 0 - 20 - 0)

HDI=

\frac{1}{2} (40 - 20)

HDI =

\frac{1}{2}  \times 20

HDI = 10

Therefore, the hydrogen deficiency index of strigol is = 10

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brainly.com/question/490531

7 0
2 years ago
how many grams of calcium sulfate are produced from 10 grams of calcium nitrate and how many grams of calcium sulfate are produc
AlekseyPX

Answer:  8.30 g of calcium sulfate are produced from 10 grams of lithium sulfate.

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} Ca(NO_3)_2=\frac{10g}{164g/mol}=0.061moles

\text{Moles of} Li_2SO_4=\frac{10g}{110g/mol}=0.091moles

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According to stoichiometry :

1 mole of Ca(NO_3)_2 require = 1 mole of Li_2SO_4

Thus 0.061 moles of Ca(NO_3)_2 will require=\frac{1}{1}\times 0.061=0.061moles  of Li_2SO_4

Thus Ca(NO_3)_2 is the limiting reagent as it limits the formation of product and Li_2SO_4 is the excess reagent.

As 1 mole of Ca(NO_3)_2 give = 1 mole of CaSO_4

Thus 0.061 moles of Ca(NO_3)_2 give =\frac{1}{1}\times 0.061=0.061moles  of CaSO_4

Mass of CaSO_4=moles\times {\text {Molar mass}}=0.061moles\times 136g/mol=8.30g

Thus 8.30 g of calcium sulfate are produced from 10 grams of lithium sulfate.

6 0
3 years ago
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